Bob publishes public key (e, N)=(43,133). Select the secret key d that corresponds to this public key. The equations below may be useful: 133 = 7.19 1 = 11·133 – 34· 43 1 = 2·108 – 4 · 43
Bob publishes public key (e, N)=(43,133). Select the secret key d that corresponds to this public key. The equations below may be useful: 133 = 7.19 1 = 11·133 – 34· 43 1 = 2·108 – 4 · 43
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Bob publishes public key (e,N)=(43,133). Select the secret key d that corresponds to this public key.
The equations below may be useful:

Transcribed Image Text:Bob publishes public key (e, N) = (43, 133). Select the secret key d that corresponds to this public key. The equations below may be useful:
133 = 7 · 19
1 = 11 · 133 - 34 · 43
1 = 2 · 108 - 4 · 43
Options:
- ○ 4
- ○ 99
- ○ 34
- ○ 104
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