Bob lost his research notebook containing the data fromthe original set of samples. Bob collects data from anew random sample of 30 aquifers and obtains a test-statistic of-2.444. Using the information from Bob's newset of data, what is the approximate P-value for Bob'shypothesis that the mean nitrogen content in aquifershas decreased due to new restrictions on waste productdisposal from poultry farms?O a. Larger than 0.1O b. Between 0.02 and 0.05O c. Larger than 0.2O d. Between 0.025 and 0.05O e. Between 0.01 and 0.025

Answered: Bob lost his research notebook…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 356 of the 579 randomly selected wildfires looked at in the south were caused by humans while 322 of the 597 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for the difference between two population proportions b. The null and alternative hypotheses would be: Ho: p1 p2 v (please enter a decimal) H1: p1 V p2 v (Please enter a decimal) c. The test statistic z v = 2.620 (please show your answer to 3 decimal places.) d. The p-value = 0.0213 e. The p-value is >v a f. Based on this, we should reject g. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) |the null hypothesis. O The results are statistically significant at a = 0.01, so there is sufficient evidence to conclude that the proportion of the 579…
The two, box and whisker diagrams below show the percentage marks obtained by two Grade 12 classes. Each class has 26 learners. Class A Class B O 10 20 30 40 50 60 70 80 90 100 The percentage marks for Class A, arranged in order, are given below: F: 58 60 62 62 63 65 65 66 66 66 66 67 69 70 71 73 73 90 [SASAMS database] 75 75 75 H 80 83 85 NOTE: Fis the lowest percentage mark H is a percentage mark between 75 and 80
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
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A sumple from a normal population with mu = 50 and sigma = 6 of M=48.20, . the sample mean.corresponds to tz = - 1.50 , then how many scores are in the sample?
SHOW YOUR SOLUTION COMPLETELY. MAKE SURE YOUR FINALS ANSWERS SHOULD BE IN 4 DECIMAL PLACES.
The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random of eight cars and runs the cars until the tires wear out. The data (in kilometers) follow. Is there any difference in mean life of these two brands of tires? Car Brand Brand 36,925 34.318 42,280 1 45.300 36,240 3 4 35.500 32,100 31,950 38,015 37.210 48,360 5 47,800 38,200 37,810 33.500 33,215 6. 7 8. 1. Is this samples independent or paired samples? Explain. 2. Write Ho and H1 3. Calculate Test statistics(T). 4. What is the critical value (T from tables)? 5. What is your conclusions if a = 0.05? 6. Estimate with 90% confidence the different in the means. Which brand would you prefer based on this calculation?
The proprietor of a greenhouse claims that its pots of lilies average 6.0 buds, with s = 0.4 buds. If n = 29 pots of lilies from a large no of pots of lilies has a mean of 5.8 buds, does this deny the proprietor’s claim of the mean number of buds at 0.015 level of significance?
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