Bob has just finished climbing a sheer cliff above a beach and wants to figure out how high he climbed. All he has to use, however, is a baseball, a stopwatch, and a friend on the ground with a long measuring tape. Bob is a pitcher, and knows that the fastest he can throw the ball is v0 = 81.0 mph. Bob starts the stopwatch as he throws the ball (with no way to measure the ball's initial trajectory) and watches carefully. The ball rises and then falls, and after t₁ = 0.710 s, the ball is once again level with Bob. Bob cannot see well enough to time when the ball hits the ground. Bob's friend then measures that the ball landed a distance of x = 365 ft from the base of the cliff. How high up is Bob if the ball started from exactly 5 ft above the edge of the cliff? Vo height of the cliff: 5 ft

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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Bob has just finished climbing a sheer cliff above a beach and wants to figure out how high he climbed. All he has to use,
however, is a baseball, a stopwatch, and a friend on the ground with a long measuring tape. Bob is a pitcher, and knows that the
fastest he can throw the ball is vo = 81.0 mph. Bob starts the stopwatch as he throws the ball (with no way to measure the ball's
initial trajectory) and watches carefully. The ball rises and then falls, and after t₁ = 0.710 s, the ball is once again level with
Bob. Bob cannot see well enough to time when the ball hits the ground. Bob's friend then measures that the ball landed a
distance of x = 365 ft from the base of the cliff. How high up is Bob if the ball started from exactly 5 ft above the edge of
the cliff?
ft
height of the cliff:
1₁
Vo
5 ft
Transcribed Image Text:Bob has just finished climbing a sheer cliff above a beach and wants to figure out how high he climbed. All he has to use, however, is a baseball, a stopwatch, and a friend on the ground with a long measuring tape. Bob is a pitcher, and knows that the fastest he can throw the ball is vo = 81.0 mph. Bob starts the stopwatch as he throws the ball (with no way to measure the ball's initial trajectory) and watches carefully. The ball rises and then falls, and after t₁ = 0.710 s, the ball is once again level with Bob. Bob cannot see well enough to time when the ball hits the ground. Bob's friend then measures that the ball landed a distance of x = 365 ft from the base of the cliff. How high up is Bob if the ball started from exactly 5 ft above the edge of the cliff? ft height of the cliff: 1₁ Vo 5 ft
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