Black smokers are found in the depths of the oceans. Thinking that the conditions in these smokers might be conducive to the formation of organic compounds, two chemists in Germany found the following reaction could occur in similar conditions. 2 CH3 SH + CO → CH3 COSCH3 + H₂S If you begin with 16.1 g of CH3 SH and excess CO, what is the theoretical yield of CH3 COSCH3? 9 CH3COSCH3 If you isolate 12.0 g of CH3 COSCH3, what is the percent yield of CH3COSCH3? %

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**Exploring Chemical Reactions in Extreme Environments: A Study**

Black smokers are fascinating geological formations found on the ocean floor. These hydrothermal vents spew out minerals and support unique ecosystems. Inspired by the extreme conditions in these smokers, two chemists in Germany conducted an experiment to see if they could recreate the formation of organic compounds under similar conditions. Their findings demonstrated that the following chemical reaction could occur:

\[ 2 \, \text{CH}_3\text{SH} + \text{CO} \rightarrow \text{CH}_3\text{COSCH}_3 + \text{H}_2\text{S} \]

### Problem 1: Theoretical Yield Calculation

To practice your skills in stoichiometry and theoretical yield calculations, consider the following scenario:

**Question:** If you begin with 16.1 g of CH\(_3\)SH and excess CO, what is the theoretical yield of CH\(_3\)COSCH\(_3\)?

\[ \boxed{\, \, \, \mathrm{g} \, \text{CH}_3\text{COSCH}_3 \, \, \, } \]

### Problem 2: Percent Yield Calculation

Let's move on to another important aspect of chemical reactions: the percent yield. Percent yield indicates the efficiency of a reaction.

**Question:** If you isolate 12.0 g of CH\(_3\)COSCH\(_3\), what is the percent yield of CH\(_3\)COSCH\(_3\)?

\[ \boxed{\, \, \, \% \, \, \, } \]
Transcribed Image Text:**Exploring Chemical Reactions in Extreme Environments: A Study** Black smokers are fascinating geological formations found on the ocean floor. These hydrothermal vents spew out minerals and support unique ecosystems. Inspired by the extreme conditions in these smokers, two chemists in Germany conducted an experiment to see if they could recreate the formation of organic compounds under similar conditions. Their findings demonstrated that the following chemical reaction could occur: \[ 2 \, \text{CH}_3\text{SH} + \text{CO} \rightarrow \text{CH}_3\text{COSCH}_3 + \text{H}_2\text{S} \] ### Problem 1: Theoretical Yield Calculation To practice your skills in stoichiometry and theoretical yield calculations, consider the following scenario: **Question:** If you begin with 16.1 g of CH\(_3\)SH and excess CO, what is the theoretical yield of CH\(_3\)COSCH\(_3\)? \[ \boxed{\, \, \, \mathrm{g} \, \text{CH}_3\text{COSCH}_3 \, \, \, } \] ### Problem 2: Percent Yield Calculation Let's move on to another important aspect of chemical reactions: the percent yield. Percent yield indicates the efficiency of a reaction. **Question:** If you isolate 12.0 g of CH\(_3\)COSCH\(_3\), what is the percent yield of CH\(_3\)COSCH\(_3\)? \[ \boxed{\, \, \, \% \, \, \, } \]
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