Homework Help is Here – Start Your Trial Now!
Engineering
Computer Engineering
blä 5 The code to find the value of S. Where A is a textbox named Atxt * and N is a textbox named Ntxt 5A + A ЗА NA S = + + | k K=4 K=3 For i=1 to val(Ntxt.text) step 2 Fori=1 to Ntxt.text step 2 S=S+(i*val(Atxt.text))/k S=S+(k*Atxt.text)/K K=i+1 K=i+1 Next i Nexti The Code is the Code is K=4 К-3 Fori=1 to Ntxt.text step 2 For i=1 to Ntxt.text step 2 S=S+(i*Atxt.text)/k k=k+1 k=i+1 S=S+(i*Atxt.text)/k Nextį Nexti The code is O the code is O

blä 5 The code to find the value of S. Where A is a textbox named Atxt * and N is a textbox named Ntxt 5A + A ЗА NA S = + + | k K=4 K=3 For i=1 to val(Ntxt.text) step 2 Fori=1 to Ntxt.text step 2 S=S+(i*val(Atxt.text))/k S=S+(k*Atxt.text)/K K=i+1 K=i+1 Next i Nexti The Code is the Code is K=4 К-3 Fori=1 to Ntxt.text step 2 For i=1 to Ntxt.text step 2 S=S+(i*Atxt.text)/k k=k+1 k=i+1 S=S+(i*Atxt.text)/k Nextį Nexti The code is O the code is O

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
See similar textbooks
icon
Related questions
Question
visual basic
blä 5 The code to find the value of S. Where A is a textbox named Atxt * and N is a textbox named Ntxt 5A + + 6. A ЗА NA S = ... k K=4 K=3 For i=1 to val(Ntxt.text) step 2 Fori=1 to Ntxt.text step 2 S=S+(i*val(Atxt.text))/k S=S+(k*Atxt.text)/K K=i+1 K=i+1 Next i Nextį The Code is the Code is K=4 K=3 For i=1 to Ntxt.text step 2 For i=1 to Ntxt.text step 2 S=S+(i*Atxt.text)/k k=k+1 k=i+1 S=S+(i*Atxt.text)/k Next į Nexti The code is the code is
Transcribed Image Text:blä 5 The code to find the value of S. Where A is a textbox named Atxt * and N is a textbox named Ntxt 5A + + 6. A ЗА NA S = ... k K=4 K=3 For i=1 to val(Ntxt.text) step 2 Fori=1 to Ntxt.text step 2 S=S+(i*val(Atxt.text))/k S=S+(k*Atxt.text)/K K=i+1 K=i+1 Next i Nextį The Code is the Code is K=4 K=3 For i=1 to Ntxt.text step 2 For i=1 to Ntxt.text step 2 S=S+(i*Atxt.text)/k k=k+1 k=i+1 S=S+(i*Atxt.text)/k Next į Nexti The code is the code is
Expert Solution
steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Computer Networking: A Top-Down Approach (7th Edi…
Computer Networking: A Top-Down Approach (7th Edi…
Computer Engineering
ISBN:
9780133594140
Author:
James Kurose, Keith Ross
Publisher:
PEARSON
Computer Organization and Design MIPS Edition, Fi…
Computer Organization and Design MIPS Edition, Fi…
Computer Engineering
ISBN:
9780124077263
Author:
David A. Patterson, John L. Hennessy
Publisher:
Elsevier Science
Network+ Guide to Networks (MindTap Course List)
Network+ Guide to Networks (MindTap Course List)
Computer Engineering
ISBN:
9781337569330
Author:
Jill West, Tamara Dean, Jean Andrews
Publisher:
Cengage Learning
Concepts of Database Management
Concepts of Database Management
Computer Engineering
ISBN:
9781337093422
Author:
Joy L. Starks, Philip J. Pratt, Mary Z. Last
Publisher:
Cengage Learning
Prelude to Programming
Prelude to Programming
Computer Engineering
ISBN:
9780133750423
Author:
VENIT, Stewart
Publisher:
Pearson Education
Sc Business Data Communications and Networking, T…
Sc Business Data Communications and Networking, T…
Computer Engineering
ISBN:
9781119368830
Author:
FITZGERALD
Publisher:
WILEY
SEE MORE TEXTBOOKS