binomial random variable X∼B(n=88,p=0.4)X∼B(n=88,p=0.4), find the probability P(X≥33)P(X≥33): P(X≥33)=P(X≥33)= (Round the answer to 4 decimal places)

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For a binomial random variable X∼B(n=88,p=0.4)X∼B(n=88,p=0.4), find the probability P(X≥33)P(X≥33):

P(X≥33)=P(X≥33)= (Round the answer to 4 decimal places)

Expert Solution
Step 1

Given that 

 X∼B(n=88,p=0.4)

Probability of success p=0.4

Number of trials n=88

 

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