Binomial Random Variables Instructions: Answer the probability questions based on the given scenario. Use the binomial distribution table. Fifteen percent of cellphone users use their cell phones to access the Internet. In a random sample of 10 cell phone users, what is the probability that: 1. Exactly 2 have used their phones to access the Internet? P(r = + V )=| 0.275897 2. More than 2 have used their phones to access the Internet? P(x 2 v )= 0.179804 3. At least 8 have used their phones to access the Internet? P(x V 8 v )= 0.000009 4. No more than 5 have used their phones to access the Internet? P(xs V)= 0.998617 * 5. Between 1 and 3 people, exclusive, have used their phones to access the Internet? P( 3 v )= 0.275897

A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Binomial Random Variables
Instructions: Answer the probability questions based on the given scenario. Use the binomial distribution table.
Fifteen percent of cellphone users use their cell phones to access the Internet. In a random sample of 10 cell phone users, what is the probability that:
1. Exactly 2 have used their phones to access the Internet? P(z = + v
v )= 0.275897
2. More than 2 have used their phones to access the Internet? P(x >
v )= 0.179804
3. At least 8 have used their phones to access the Internet? P(x -=> V
v )= 0.000009
4. No more than 5 have used their phones to access the Internet? P(xs
V. )= 0.998617
3
* 5. Between 1 and 3 people, exclusive, have used their phones to access the Internet? P( 1
0.275897
Transcribed Image Text:Binomial Random Variables Instructions: Answer the probability questions based on the given scenario. Use the binomial distribution table. Fifteen percent of cellphone users use their cell phones to access the Internet. In a random sample of 10 cell phone users, what is the probability that: 1. Exactly 2 have used their phones to access the Internet? P(z = + v v )= 0.275897 2. More than 2 have used their phones to access the Internet? P(x > v )= 0.179804 3. At least 8 have used their phones to access the Internet? P(x -=> V v )= 0.000009 4. No more than 5 have used their phones to access the Internet? P(xs V. )= 0.998617 3 * 5. Between 1 and 3 people, exclusive, have used their phones to access the Internet? P( 1 0.275897
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