binomial random variable random variable X reveals μ = 20 and σ^2 = 4. Calculate probability that X =21
Q: X denotes a binomial random variable with parameters n and p, Indicate which area under the…
A:
Q: What is the probability that a leatherback turtle will weight more than 1000 pounds
A: Given that X follows N(mean = 760, SD = 98), then Z = (X - mean)/SD follows N(0,1)
Q: Assume that for the population of MBA (Supply Chain Management), the average starting salary is PKR…
A: Points on sampling distribution of the sample mean: If the true population distribution of a random…
Q: The time spent waiting in the line is approximately normally distributed. The mean waiting time is 6…
A: Solution
Q: The # of flaws in copper wire (X), follows a Poisson Distribution with a rate of 1.5 flaws per mm.…
A:
Q: The strength of the cubic concrete of the first line production is 110 N/mm² and standard deviation…
A: Let 'X' represent the strength of the cubic concrete of the first line production, and 'Y' represent…
Q: Two aiplanes are flying in the same drection in adjacent paralel coridors. At tine t0, the first…
A: Given: Speed of 1st plane defined by X1 which follows the normal distribution X1~N525, 8μ1=525σ1=8…
Q: The distribution of the scores on a certain exam is N(50,10),which means that the exam scores are…
A:
Q: A recent study found that the life expectancy of a people living in Africa is normally distributed…
A: From the provided information,
Q: Find the probability that the mean of this sample will be more than 130 between 120 and 125 between…
A: It is given that: Population Mean =μ= 120 Standard deviation = σ=18 Sample size =n= 64 Sample…
Q: An electric firm manufactures light bulbs that have a length of life that is approximately normally…
A:
Q: Assume the random variable x is normally distributed with mean u = 86 and standard deviation =4.…
A: Given,mean(μ)=86standard deviation(σ)=4
Q: For a normally distributed random variable with mean is 44 and standard deviation is 15, Find the Z…
A: Answer: From the given data, mean (μ) = 44 Standard deviation(σ) = 15
Q: For a normally distributed random variable, the population mean is 8 and population standard…
A:
Q: The mean of Binomial distribution is 3 and variance is-. Find P(1 s x < 6)
A:
Q: The variable X denotes a binomial random variable with parameters n and p. Indicate which area under…
A: given data x is binomial distribution with parameter n and p . under normal approximation which area…
Q: Suppose that X is a continuous random variable that follows a normal dis- tribution with mean 68. If…
A: Solution: Let X be the continuous random variable having normal distribution with mean μ= 68…
Q: second one. Suppose the speed of the first plane (km/hr) is normally distributed with mean 550 and…
A:
Q: Tom works for a fruit company and found that the weight of pineapples are normally distributed with…
A: From the information, mean is 500 and standard deviation is 100.
Q: Assume the random variablex is normally distrubited with mean u=85 and the standard deviation o=5.…
A: Population mean μ =85 Population standard deviation =5
Q: There is a 5k race, time was normally distributed with a mean of 28 minutes and a sd of 5 minutes.…
A: It is given thatMean, μ = 28Standard deviation, σ = 5Z-Score, Z = ( X - μ )/σwhere, Z be the…
Q: The Proportion of during the Month whith Stationary supply Sold beta random Variable a d = 4 and B=2…
A: Given: X~Beta(α=4,β=2) Formula Used: The probability density function of beta distribution is…
Q: mean equal to 800MPA and a standard deviation of 40 MPa before it reaches yielding. Find the…
A: Random variable: A random variable X is a real number that describes the outcome of the random…
Q: An electrical firm manufactures light bulbs that have a life, before burn-out, thatis normally…
A:
Q: Independent random samples of ?=15n=15 observations each are drawn from normal populations. The…
A: We have given that Independent random samples of n=15 observations each are drawn from normal…
Q: Daily sales of a store is normally distributed with mean u=180 Rials and variance o? =100. Find the…
A: From the provided information, Mean (µ) = 180 Rials Variance (σ2) = 100 Let X be a random variable…
Q: A random variable is normally distributed with a mean of μ = 50 and a standard deviation of σ = 5.…
A: Given Mean(μ)=50standard deviation(σ)=5
Q: The average number of miles (in thousands) that a car's tire will function before needing…
A:
Q: females have pulse rates that are normally distributed with a mean of 75.0 beats per minute and a…
A: Females have pulse rate normally distributed with mean of 75.0 beats per minute with standard…
Q: X is the Binomial Random Variable which counts the number of students who passed an exam. If the…
A: Given n=81 P=0.85
Q: Let the random variable X follows binomial distribution with parameters 14 and 5/12.
A: given information: n=14 p=5/12=0.41666 we wants to calculate P( X≥2) P(X≥2 )=∑i=214nCxi *pxi…
Q: A random variable follows a binomial distribution with a probability of success equal to 0.62. For a…
A: Given data, p=0.62 n=7 standard deviation σ =?
Q: Assume the random variable x is normally distributed with mean equals=84 and standard deviation…
A: z-score:A z-score is a standard score that describes the number of standard deviation away from its…
Q: If the mean number of people visiting a reservation counter is at any given hour is 6, then using…
A: Formula : poisson distribution is given by
Q: Suppose a random variable, x, follows a Poisson distribution. Let µ=2.5 every minute, find the…
A:
Q: The length of time for a college applicant to complete the college achievement test is normally…
A: Given: Mean = 70 minutes Variance = 144 min2 To find: The probability of selecting an applicant at…
Q: The mean weight of a fire ant worker is 3.11 mg with a standard deviation of .49 mg. Suppose we…
A:
Q: A random variable follows binomial distribution with parameters n = 43 and p= 0.56 Find the mean…
A: From the provided information, Sample size (n) = 43 And p = 0.56
Q: A random sample of n - 4 scores is obtained from a normal population with u = 30 and o- 8. What…
A: Let us assume that the The population is denoted by X which is normally distributed. So, by the…
Q: Blood type AB is found in only 3% of the population†. If 215 people are chosen at random, find the…
A:
Q: The average number of mosquitos in a stagnant pond is 80 per square meter with a standard deviation…
A: Given that, x be the number of mosquitos ina stagnant has a normal distribution with mean =80 per…
A binomial random variable random variable X reveals μ = 20 and σ^2 = 4. Calculate
Step by step
Solved in 3 steps with 1 images
- The personality variable extraversion is normally distributed in the population and has a mean of 10 and a standard deviation of 2. Researchers consider individuals who are 1 standard deviation above the mean “highly” extroverted. What is the probability that you can randomly sample 3 people from the population and all 3 would be “highly” extroverted? Show relevant work.The average number of miles (in thousands) that a car's tire will function before needing replacement is 68 and the standard deviation is 19. Suppose that 42 randomly selected tires are tested. Round all answers to 4 decimal places where possible and assume a normal distribution. If a randomly selected individual tire is tested, find the probability that the number of miles (in thousands) before it will need replacement is between 65 and 68.6. For the 42 tires tested, find the probability that the average miles (in thousands) before need of replacement is between 65 and 68.6. For part b, is the assumption that the distribution is normal necessary? NoYesthe average height of elementary school children is 42 inches with a standard deviation of 4.32 random sample of 30 children from this school, find the probability that their mean height is greater than 40 inches.
- Let X be a random variable that represents the level of glucose in the blood (milligrams per deciliter of blood). The distribution of X for a healthy person is normally distributed with men u = 85 and standard deviation o = 25. A person suffers from severe excess in insulin would have a lower level of glucose. A blood test with result of X < 40 would be used as an indicator that medication is needed. (a) What is the probability that a healthy person will be suggested with medication after a single test? (b) A doctor uses the average result of 2 tests for diagnosis, that is X. The second test will be conducted one week after the first test, so that the two test results are independent. For many healthy persons, each has finished two tests, find the expectation and standard error of the distribution of X. (c) The doctor suggests medication will be given only when the average level of glucoses in the 2 blood tests is less than 40, that is X < 40, so to reduce the chance of…Suppose that the duration of a particular type of criminal trial is known to be normally distributed with a mean of 21 days and a standard deviation of seven days. (a) In words, define the random variable X. Edit Insert Formats BIUX₂ + 2+ 3 = C P & (b) Find the z-score for a trial lasting 19 days. your answer to three decimal places.) Shade: Left of a value (c) If one of the trials is randomly chosen, find the probability that it lasted at least 19 days. +||||||||| (d) Shade the area corresponding to this probability in the graph below. (Hint: The x- axis is the z-score. Use your z-score from part (b), rounded to one decimal place). -1 X² A ▾ A▾ -1.5 用 Σ+ Σ Α 2 Click and drag the arrows to adjust the values. (Round ++++++++++++ 3 4 (e) eighty-eight percent of all trials of this type are completed within how many days?The number of people who dine at restaurants in Buffalo is normally distributed with a µ = 30 people and = 3 people. (Report both the z-scores and probability) What is the probability that the mean of 7 restaurants will have between 21 and 32 people dining there? z1 = z2 = p(21 > M > 32) = What is the probability that the mean of 13 restaurants will have less than 21 people dining there? z = p(M < 21)= Is the p=0 when the z score is extreme like -10 or 10?
- Please do not give solution in image formate thanku.Use this information about the overhead reach distances of adult females: µ = 205.5 cm, σ = 8.6 cm, and overhead reach distances are normally distributed (based on data from th Federal Aviation Administration) If 40 adult females are randomly selected, find the probability that they have a mean overhead reach between 204.0 cm and 206.0 cm.Don't know how to solve
- Suppose that f(x)=2/(3^x), x=1,2,3,... is the probability function for a random variable X. Find P(X>3). Use 4 decimal places.Supposed random variable X has a Binomial distribution with 10 trials and probability of success = 0.4. What is E(X)?Assume the random variable x is normally distributed with mean u = 85 and standard deviation o = 4. Find the indicated probability. P(x<81) P(x<81)= (Round to four decimal places as needed.) %3D Enter your answer in the answer box. Copyright 2020 Pearson Education Inc. All rights reserved. / Permissions Contact Us / dtv A 多 CO
