(Big-O Analysis) Total number of comparisons in algorithm A is 2n² +n+1 and total number of comparisons in algorithm B is 2nlog(n) + 8n², where 'n' is input size. (The base of log is 2). Order of algorithm A is O( (a)). Order of algorithm B is O((b)). What is (a) and (b) ? O (a): n2, (b): n2 o (a): n2, (b): nlog(n) (a): n. (b): nlog(n) o (a): n+n, (b): log(n)

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