Benny's Barber Shop in Cleveland has five chairs for waiting customers. Previous records indicate that the probablity distribution for the number of customers waiting, Y, is as follows. 0 1 2 3 4 5 Y P(Y=y) 0.419 0.160 0.137 0.110 0.096 0.078 What is the probability that exactly four customers are waiting? What is the probability that more than four customers are waiting? What is the probability that at most four customers are waiting? What is the probability that at least four customers are waiting? Find P(1≤Y<4).
Benny's Barber Shop in Cleveland has five chairs for waiting customers. Previous records indicate that the probablity distribution for the number of customers waiting, Y, is as follows. 0 1 2 3 4 5 Y P(Y=y) 0.419 0.160 0.137 0.110 0.096 0.078 What is the probability that exactly four customers are waiting? What is the probability that more than four customers are waiting? What is the probability that at most four customers are waiting? What is the probability that at least four customers are waiting? Find P(1≤Y<4).
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
![Benny's Barber Shop in Cleveland has five chairs for waiting customers. Previous records indicate that the probablity
distribution for the number of customers waiting, Y, is as follows.
0
1
2
3
4
5
Y
P(Y=y) 0.419 0.160 0.137 0.110 0.096 0.078
What is the probability that exactly four customers are waiting?
What is the probability that more than four customers are waiting?
What is the probability that at most four customers are waiting?
What is the probability that at least four customers are waiting?
Find P(1≤Y<4).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a8023c3-c690-4e2c-b9f1-72fb581950b4%2F37379728-3813-444f-b7c7-874a2f6d38d7%2Fu33ad7c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Benny's Barber Shop in Cleveland has five chairs for waiting customers. Previous records indicate that the probablity
distribution for the number of customers waiting, Y, is as follows.
0
1
2
3
4
5
Y
P(Y=y) 0.419 0.160 0.137 0.110 0.096 0.078
What is the probability that exactly four customers are waiting?
What is the probability that more than four customers are waiting?
What is the probability that at most four customers are waiting?
What is the probability that at least four customers are waiting?
Find P(1≤Y<4).
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