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below point in the direction of the electric field. The path of the charge is shown in blue. Xuy 45% E = 7(-Ĵ)N/C AVEO 1.9 m 45% 1.6 m Which of the following is the correct expression for AV? 45° AX11 A) AV = -(7N/C)(1.9m) cos(45°) B) AV = −e(7N/C)(1.9m) cos(45°) c) AV = −(7N/C)(1.9m)–(7N/C)(1.6m) D)AV = e(7N/C)(1.9m)-e(7N/C)(1.6m) E) AV = -(7N/C)(1.9m) cos(45°)-(7N/C)(1.6m) AX AV=- E• AX₁ "Ar

below point in the direction of the electric field. The path of the charge is shown in blue. Xuy 45% E = 7(-Ĵ)N/C AVEO 1.9 m 45% 1.6 m Which of the following is the correct expression for AV? 45° AX11 A) AV = -(7N/C)(1.9m) cos(45°) B) AV = −e(7N/C)(1.9m) cos(45°) c) AV = −(7N/C)(1.9m)–(7N/C)(1.6m) D)AV = e(7N/C)(1.9m)-e(7N/C)(1.6m) E) AV = -(7N/C)(1.9m) cos(45°)-(7N/C)(1.6m) AX AV=- E• AX₁ "Ar

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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CQ3: A proton moves through a uniform electric field of magnitude 7.0 N/C. The arrows below point in the direction of the electric field. The path of the charge is shown in blue. Ē = 7(-ĵ)N/C P 3 AVEO 1.9 m 45° P2 450 1.6 m Which of the following is the correct expression for AV? 450 AX11 11 AKI A) AV = -(7N/C)(1.9m) cos(45°) B) AV = −e(7N/C)(1.9m)cos(45°) c) AV = −(7N/C)(1.9m)–(7N/C)(1.6m) D) AV = −e(7N / C)(1.9m) – e(7N/C)(1.6m) E) AV = -(7N/C)(1.9m) cos(45°)-(7N/C)(1.6m) 26 AX AV=- E• AX₁1 - 9
Transcribed Image Text:CQ3: A proton moves through a uniform electric field of magnitude 7.0 N/C. The arrows below point in the direction of the electric field. The path of the charge is shown in blue. Ē = 7(-ĵ)N/C P 3 AVEO 1.9 m 45° P2 450 1.6 m Which of the following is the correct expression for AV? 450 AX11 11 AKI A) AV = -(7N/C)(1.9m) cos(45°) B) AV = −e(7N/C)(1.9m)cos(45°) c) AV = −(7N/C)(1.9m)–(7N/C)(1.6m) D) AV = −e(7N / C)(1.9m) – e(7N/C)(1.6m) E) AV = -(7N/C)(1.9m) cos(45°)-(7N/C)(1.6m) 26 AX AV=- E• AX₁1 - 9
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