Below is the reaction for the evaporation of water: H20 (1) → H20 (g) AH°f H2O (1)= -285.8 kJ/mole; H20 (g) = -241.8 kJ/mole %3D Calculate AH°rxn for this process. This is the reaction that happens when your sweat evaporates. Why is this a cooling mechanism for your body? How much sweat would have to evaporate from a persons skin to cool the body by 0.5°C? Assume this person has a body mass of 150 Ibs and the specific heat capacity of the body is 4.0 J/g °C. 1 lb. = 0.454 kg

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Below is the reaction for the evaporation of water.
H2O (I) H20 (g)
AH°f H2O (1)= -285.8 kJ/mole ; H20 (g) = -241.8 kJ/mole
%3D
Calculate AH*rxn for this process.
This is the reaction that happens when your sweat evaporates. Why is
this a cooling mechanism for your body?
How much sweat would have to evaporate from a person's skin to
cool the body by 0.5 C? Assume this person has a body mass of 150
Ibs and the specific heat capacity of the body is 4.0 J/g °C. 1 Ib. =
0.454 kg
Transcribed Image Text:Below is the reaction for the evaporation of water. H2O (I) H20 (g) AH°f H2O (1)= -285.8 kJ/mole ; H20 (g) = -241.8 kJ/mole %3D Calculate AH*rxn for this process. This is the reaction that happens when your sweat evaporates. Why is this a cooling mechanism for your body? How much sweat would have to evaporate from a person's skin to cool the body by 0.5 C? Assume this person has a body mass of 150 Ibs and the specific heat capacity of the body is 4.0 J/g °C. 1 Ib. = 0.454 kg
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