Below is the function f(x). 6- 4 3 2 1 -7-6-5-4-3-2-1 12 3 4 6 -1 пр * -5- -6 Over which interval of a values is f'> 0? ○ (3,∞) ○ [3,∞) 0(-0,3) 0 (-0,3] 0 (-00,00] Over which interval of a values is f'< 0? ○ (3,∞) ○ [3,∞) O(-∞,3) 0 (-0,3] 0 (-00,00] Over the interval (-∞, ∞), this function is concave up (f">0) concave down (f" < 0)

Q: Let f(x) be a function with domain (-00, 3) U (3,00). Use the graph of f'(x) below to determine the…

A: Step 1:

Q: The graph of function f(x) = x³ 6x2 + 9x + 1 is concave upward on (-∞, 2) (-0, 0) (2, оо) о (-2, 2)

A: f is concave up when f''(x) is greater than 0

Q: Let f(x) be a function with domain (-00, 00) and f'(x) = the intervals where f is decreasing. OA B…

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Q: If f is one-to-one and f( – 3) = 12, then f-'(12) and (f( – 3))¯

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Q: (3, -13. -mplete the following statements. x) > 0 on the interval(s) x) 0 on the interval(s)

A: Solution of the problem as follows

Q: es of f'(-7), f'(-4) & f'(-2)

A: at x= -7 graph is increasing At x = -4 graph gives local Maxima At x = -2 graph is decreasing

Q: What are intervals of concavity of the function f(x) = -2x + 6x² – 3 ? a. Concave upward on (-1, o0)…

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Q: where the natural number n is called the degree of the polynomial. For polynomials P and Q, we can…

A: Given that,Px=3Qx=x3Px+Qx=3+x3

Q: Consider the function f (x) =/2-x+5 for the domain (-x %3D Find f'(x), where f is the inverse of f.…

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Q: S x²(In x)²dx

A: We can solve the integration as below using integration by-parts.