Below is the answer that I have but it is incorrect can anyone help? select PROJ_NUM, ROUND(SUM(ASSIGN_HOURS),2) as 'TOTAL_HOURS', ROUND(SUM(ASSIGN_CHARGE),2) as 'TOTAL_CHARGE' from ASSIGNMENT -- from ASSIGNMENT table group by PROJ_NUM; -- group by to aggregate per PROJ_NUM
Below is the answer that I have but it is incorrect can anyone help? select PROJ_NUM, ROUND(SUM(ASSIGN_HOURS),2) as 'TOTAL_HOURS', ROUND(SUM(ASSIGN_CHARGE),2) as 'TOTAL_CHARGE' from ASSIGNMENT -- from ASSIGNMENT table group by PROJ_NUM; -- group by to aggregate per PROJ_NUM
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
Below is the answer that I have but it is incorrect can anyone help?
select PROJ_NUM, ROUND(SUM(ASSIGN_HOURS),2) as 'TOTAL_HOURS', ROUND(SUM(ASSIGN_CHARGE),2) as 'TOTAL_CHARGE'
from ASSIGNMENT -- from ASSIGNMENT table
group by PROJ_NUM; -- group by to aggregate per PROJ_NUM

Transcribed Image Text:PROJ_NUM
15
18
22
SQL Viewer
25
+
TOTAL_HOURS
20.50
23.70
27.00
19.40
TOTAL_CHARGE
1806.52
1544.80
2593.16
1668.16

Transcribed Image Text:Problem 7
Write a query to produce the total number of hours and charges for each of the projects
represented in the ASSIGNMENT table, sorted by project number. The output is shown in Figure
P7.7.
PROJ NUM
15
18
22
25
SumOfASSIGN HOURS
20.5
23.7
27.0
19.4
Figure P7.7
Task
SumOfASSIGN_CHARGE
1806.52
1544.80
2593.16
1668.16
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