A hydrogen atom is in its ground state. Incident on the atom is a photon having an energy of 3.4 eV. What is the result? The electron makes a transition from the n = 1 to n = 2 energy level. The electron makes a transition from the n∞ to n = 2 energy level. The atom is ionized. The photon passes by the atom without interaction. Below is an energy-level diagram for the hydrogen atom. n=co n=4 n=3 n=2 E=0 E = -0.85 eV E=-1.51 eV E = -3.40 eV n=1 E = -13.6 eV
A hydrogen atom is in its ground state. Incident on the atom is a photon having an energy of 3.4 eV. What is the result? The electron makes a transition from the n = 1 to n = 2 energy level. The electron makes a transition from the n∞ to n = 2 energy level. The atom is ionized. The photon passes by the atom without interaction. Below is an energy-level diagram for the hydrogen atom. n=co n=4 n=3 n=2 E=0 E = -0.85 eV E=-1.51 eV E = -3.40 eV n=1 E = -13.6 eV
Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter9: Atomic Structure
Section: Chapter Questions
Problem 7Q
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