A hydrogen atom is in its ground state. Incident on the atom is a photon having an energy of 3.4 eV. What is the result? The electron makes a transition from the n = 1 to n = 2 energy level. The electron makes a transition from the n∞ to n = 2 energy level. The atom is ionized. The photon passes by the atom without interaction. Below is an energy-level diagram for the hydrogen atom. n=co n=4 n=3 n=2 E=0 E = -0.85 eV E=-1.51 eV E = -3.40 eV n=1 E = -13.6 eV
A hydrogen atom is in its ground state. Incident on the atom is a photon having an energy of 3.4 eV. What is the result? The electron makes a transition from the n = 1 to n = 2 energy level. The electron makes a transition from the n∞ to n = 2 energy level. The atom is ionized. The photon passes by the atom without interaction. Below is an energy-level diagram for the hydrogen atom. n=co n=4 n=3 n=2 E=0 E = -0.85 eV E=-1.51 eV E = -3.40 eV n=1 E = -13.6 eV
Modern Physics
3rd Edition
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Chapter9: Atomic Structure
Section: Chapter Questions
Problem 7Q
Related questions
Question

Transcribed Image Text:A hydrogen atom is in its
ground state. Incident on
the atom is a photon
having an energy of 3.4
eV. What is the result?
The electron
makes a
transition from
the n = 1 to n =
2 energy level.
The electron
makes a
transition from
the n∞ to n
= 2 energy level.
The atom is
ionized.
The photon
passes by the
atom without
interaction.

Transcribed Image Text:Below is an energy-level
diagram for the hydrogen
atom.
n=co
n=4
n=3
n=2
E=0
E = -0.85 eV
E=-1.51 eV
E = -3.40 eV
n=1
E = -13.6 eV
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