Below is a simplified version of the Theorell-Chance mechanism for the metabolism of ethanol (A) to acetaldehyde (product), catalyzed by alcohol dehydrogenase. The reaction also involves the reduction of NAD+ (B) to NADH (C) , so the mechanism accounts for the fact that the reaction is bimolecular, not including the enzyme. E + A EA (fast) EA +BA EZ + C (fast) EZ - E + Product (slow) • Part A It is known that the rate-determining step is the formation of products so that the equilibria in the first two steps are relatively fast. Assume that the rate of the forward reactions equal the rates of the reverse reactions in each of the first two steps and obtain an expression for the rate of the reaction. Drag the appropriate labels to their respective targets. Reset Help kak3 E][A]|B] k-k-¿E][B] kıkakz EA] Rate = kıkakajC)

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Below is a simplified version of the Theorell-Chance mechanism for the metabolism of ethanol (A) to acetaldehyde (product), catalyzed by alcohol dehydrogenase. The reaction also involves the reduction of NAD+ (B) to
NADH (C) , so the mechanism accounts for the fact that the reaction is bimolecular, not including the enzyme.
E + A
EA
(fast)
EA + B
EZ + C
(fast)
EZ → E + Product
(slow)
• Part A
It is known that the rate-determining step is the formation of products so that the equilibria in the first two steps are relatively fast. Assume that the rate of the forward reactions equal the rates of the reverse reactions in each of the first two steps and obtain an
expression for the rate of the reaction.
Drag the appropriate labels to their respective targets.
Reset Help
kıkak3 E][A][B]
k-k-¿E][B]
kık2k3[EA]
Rate =
k-k–¿C]
kıkk3[C]
kikzk3 E][A]
Transcribed Image Text:Review Periodic Table Below is a simplified version of the Theorell-Chance mechanism for the metabolism of ethanol (A) to acetaldehyde (product), catalyzed by alcohol dehydrogenase. The reaction also involves the reduction of NAD+ (B) to NADH (C) , so the mechanism accounts for the fact that the reaction is bimolecular, not including the enzyme. E + A EA (fast) EA + B EZ + C (fast) EZ → E + Product (slow) • Part A It is known that the rate-determining step is the formation of products so that the equilibria in the first two steps are relatively fast. Assume that the rate of the forward reactions equal the rates of the reverse reactions in each of the first two steps and obtain an expression for the rate of the reaction. Drag the appropriate labels to their respective targets. Reset Help kıkak3 E][A][B] k-k-¿E][B] kık2k3[EA] Rate = k-k–¿C] kıkk3[C] kikzk3 E][A]
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