Below is a simplified version of the Theorell-Chance mechanism for the metabolism of ethanol (A) to acetaldehyde (product), catalyzed by alcohol dehydrogenase. The reaction also involves the reduction of NAD+ (B) to NADH (C) , so the mechanism accounts for the fact that the reaction is bimolecular, not including the enzyme. E + A EA (fast) EA +BA EZ + C (fast) EZ - E + Product (slow) • Part A It is known that the rate-determining step is the formation of products so that the equilibria in the first two steps are relatively fast. Assume that the rate of the forward reactions equal the rates of the reverse reactions in each of the first two steps and obtain an expression for the rate of the reaction. Drag the appropriate labels to their respective targets. Reset Help kak3 E][A]|B] k-k-¿E][B] kıkakz EA] Rate = kıkakajC)
Catalysis and Enzymatic Reactions
Catalysis is the kind of chemical reaction in which the rate (speed) of a reaction is enhanced by the catalyst which is not consumed during the process of reaction and afterward it is removed when the catalyst is not used to make up the impurity in the product. The enzymatic reaction is the reaction that is catalyzed via enzymes.
Lock And Key Model
The lock-and-key model is used to describe the catalytic enzyme activity, based on the interaction between enzyme and substrate. This model considers the lock as an enzyme and the key as a substrate to explain this model. The concept of how a unique distinct key only can have the access to open a particular lock resembles how the specific substrate can only fit into the particular active site of the enzyme. This is significant in understanding the intermolecular interaction between proteins and plays a vital role in drug interaction.
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Periodic Table
Below is a simplified version of the Theorell-Chance mechanism for the metabolism of ethanol (A) to acetaldehyde (product), catalyzed by alcohol dehydrogenase. The reaction also involves the reduction of NAD+ (B) to
NADH (C) , so the mechanism accounts for the fact that the reaction is bimolecular, not including the enzyme.
E + A
EA
(fast)
EA + B
EZ + C
(fast)
EZ → E + Product
(slow)
• Part A
It is known that the rate-determining step is the formation of products so that the equilibria in the first two steps are relatively fast. Assume that the rate of the forward reactions equal the rates of the reverse reactions in each of the first two steps and obtain an
expression for the rate of the reaction.
Drag the appropriate labels to their respective targets.
Reset Help
kıkak3 E][A][B]
k-k-¿E][B]
kık2k3[EA]
Rate =
k-k–¿C]
kıkk3[C]
kikzk3 E][A]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe25b220f-7118-4ca5-b302-f1bc6bf0b2a6%2Fe76bf679-4d42-4b42-8296-45c15039e1ff%2Fp0rqy3c_processed.png&w=3840&q=75)

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