ALEKS -Data-Onven Decisions NXA ALEKS - Chlorette Williams - Lear X->O https://www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-lgNslkr7j8P3jH-v-6txjbonmDn7WsVrRAXK6XnHkiRvH2tIBo1RdLW9Peg2eBeNg_rdIGA. Q taRANDOM VARIALES AND DISTRIBUTIONSNormal versus standard normal curvesChlorette ysBelow is a graph of a normal distribution with mean u=-4 and standard deviation a =4. The shaded region represents the probability of obtaining a valuefrom this distribution that is between -12 and 2.Shade the corresponding region under the standard normal curve below.ExplanationCheckO 2022 McGraw HI LLC AlI Rights Reserved Terms of Use I Privecy Center| AccessibilityO Type here to search(?)27°F A Ohp"ort sedeletehome8backspacePH KLpausealtett

Answered: Image /qna-images/answer/374d9949-9e8c-46c8-bcab-b4adddb45efd.jpg

Answered: Below is a qgraph of a normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The length of a movie file that is available for streaming is modeled using the normal distribution shown below. The mean of the distribution is 170.5 min and the standard deviation is 19.9 min, In the figure, V is a number along the axis and is under the highest part of the curve. And, U and W are numbers along the axis that are each the same distance away from V. Use the empirical rule to choose the best value for the percentage of the area under the curve that is shaded, and find the values of U, V, and W. Percentage of total area shaded: (Choose one) 100 120 140 160 180 200 220 240 ( min)
The average THC content of marijuana sold on the street is 9.7%.Suppose the THC content is normally distributed with a standard deviation of 2%.Let X be the THC content for a randomly selected bag of marijuana that is sold on the street.Round 4 decimal places when possible. Find the probability that a randomly selected bag of marijuana sold on the street will have a THC content greater than 10.9 Find the 62nd percentile for this distribution
A distribution of values is normal with a mean of 137.6 and a standard deviation of 55.7.Find P72, which is the score separating the bottom 72% from the top 28%.P72 = Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Use the normal distribution of IQ scores, which has a mean of 100 and a standard deviation of 18, and the following table with the standard scores and percentiles for a normal distribution to find the indicated quantity. Percentage of scores less than 145 is __% (round to two decimal places as needed)
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 239.7-cm and a standard deviation of 0.8-cm. For shipment, 5 steel rods are bundled together.Find P58, which is the average length separating the smallest 58% bundles from the largest 42% bundles. P58 = -cmEnter your answer as a number accurate to 2 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
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Below is a graph of a normal distribution with mean u = 5 and standard deviation σ = 4. The shaded region represents the probability of obtaining a value from this distribution that is greater than -1. 0.2+ Shade the corresponding region under the standard normal curve below. Check B A × S 8 00 Save For Later Submit Assignment © 2024 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Accessibility Q Search L IA W
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A distribution of values is normal with a mean of 173.5 and a standard deviation of 99.3.Find P3, which is the score separating the bottom 3% from the top 97%.P3 = Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Some students paid a private tutor to help them improve their results on a certain mathematical test. These students had a mean change in score of + 18 points, with a standard deviation of 68 points. In a random sample of 100 students who pay a private tutor to help them improve their results, what is the likelihood that the change in the sample mean score is less than 10 points? Click the icon to view the table of normal curve areas. Normal Curve Areas P(x< 10) = (Round to three decimal places as needed.) 0. .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 .0000 .0398 .0793 .1179 .1554 .1915 .0 .1 .0040 .0438 .0080 .0478 .0871 1255 .0160 .0557 .0948 .1331 .1700 2054 .0120 .0517 .0199 .0596 0987 1368 .1736 2088 .0239 .0636 1026 .1406 1772 2123 0279 .0675 1064 1443 1808 2157 .0319 0714 .1103 1480 1844 2190 0359 .0753 1141 1517 1879 2224 .2 .3 .0832 .1217 .1591 1950 .0910 1293 1664 1628 .5 .1985 2019 .2257 .2580 .2881 .3159 3413 2291 2611 .6 .7 .8 .9 1.0 2324 2642 2939 3212 3461 2357 2673 2967…
i just can never get graphs

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