Bellman Ford Algorithm (1, part 2). Consider the scenario shown below, where at t=1, node e receives distance vectors from neighboring nodes d, b, h and f. The (old) distance vector at e (the node at the center of the network) is also shown, before receiving the new distance vector from its neighbors. Indicate which of the components of new distance vector at e below have a value of 2 after e has received the distance vectors from its neighbors and updated its own distance vector.
Bellman Ford Algorithm (1, part 2). Consider the scenario shown below, where at t=1, node e receives distance vectors from neighboring nodes d, b, h and f. The (old) distance vector at e (the node at the center of the network) is also shown, before receiving the new distance vector from its neighbors. Indicate which of the components of new distance vector at e below have a value of 2 after e has received the distance vectors from its neighbors and updated its own distance vector.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
5.04-2. Bellman Ford
![DV in d:
Dd(a) = 1
Dd(b) = 00
Dd(c) = ∞
Dd(d) = 0
Dale) = 1
Dd(f) = ∞
Da(g) = 1
Do(h) = 00
Do(i) = ∞
DV in h:
D₁(a) = ∞
D₁(b) = 00
Dh(c) = 00
Dh(d) = 00
D₁(e) = 1
D₁(f) = 00
Dn(g) = 1
Dm(h) = 0
Dh(i) = 1
De(g)
De(a)
De(i)
De(b)
De(c)
De(f)
De(h)
De(d)
1
at t=1 e receives
DVS from b, d, f, h
8
1
1
compute
1
Q: what is new DV computed in e at
t=1?
-h
Db(a)=8
Db(c) = 1
Do(d) = ∞
Db(e) = 1
1
DV in b:
1
D₂(f) = ∞0
Db(g) = 00
D₁(h) = ∞0
D₂(i) = 00
1
old DV at e
DV in e:
De(a) = ∞
D₂(b) = 1
De(c)
De(d) = 1
De(e) = 0
De(f) = 1
= ∞0
De(g)
De(h) = 1
De(i) = ∞
DV in f:
Di(a) = ∞
D₁(b) = 00
D(c) = 00
Di(d) = ∞
Di(e) = 1
Di(f) = 0
= ∞
Dig)=
Di(h) = 00
D(i) = 1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6b67a6a2-2d8c-4553-99c2-3c44a5ebdd4f%2Fbb201955-f093-48f4-979c-e8602ba635d7%2F2lntc21_processed.png&w=3840&q=75)
Transcribed Image Text:DV in d:
Dd(a) = 1
Dd(b) = 00
Dd(c) = ∞
Dd(d) = 0
Dale) = 1
Dd(f) = ∞
Da(g) = 1
Do(h) = 00
Do(i) = ∞
DV in h:
D₁(a) = ∞
D₁(b) = 00
Dh(c) = 00
Dh(d) = 00
D₁(e) = 1
D₁(f) = 00
Dn(g) = 1
Dm(h) = 0
Dh(i) = 1
De(g)
De(a)
De(i)
De(b)
De(c)
De(f)
De(h)
De(d)
1
at t=1 e receives
DVS from b, d, f, h
8
1
1
compute
1
Q: what is new DV computed in e at
t=1?
-h
Db(a)=8
Db(c) = 1
Do(d) = ∞
Db(e) = 1
1
DV in b:
1
D₂(f) = ∞0
Db(g) = 00
D₁(h) = ∞0
D₂(i) = 00
1
old DV at e
DV in e:
De(a) = ∞
D₂(b) = 1
De(c)
De(d) = 1
De(e) = 0
De(f) = 1
= ∞0
De(g)
De(h) = 1
De(i) = ∞
DV in f:
Di(a) = ∞
D₁(b) = 00
D(c) = 00
Di(d) = ∞
Di(e) = 1
Di(f) = 0
= ∞
Dig)=
Di(h) = 00
D(i) = 1
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