Bellman Ford Algorithm (1, part 2).  Consider the scenario shown below, where at t=1, node e receives distance vectors from neighboring nodes d, b, h and f.  The (old) distance vector at e (the node at the center of the network) is also shown, before receiving the new distance vector from its neighbors.  Indicate which of the components of new distance vector at e below have a value of 2 after e has received the distance vectors from its neighbors and updated its own distance vector.

Database System Concepts
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ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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5.04-2. Bellman Ford Algorithm (1, part 2).  Consider the scenario shown below, where at t=1, node e receives distance vectors from neighboring nodes d, b, h and f.  The (old) distance vector at e (the node at the center of the network) is also shown, before receiving the new distance vector from its neighbors.  Indicate which of the components of new distance vector at e below have a value of 2 after e has received the distance vectors from its neighbors and updated its own distance vector.  

DV in d:
Dd(a) = 1
Dd(b) = 00
Dd(c) = ∞
Dd(d) = 0
Dale) = 1
Dd(f) = ∞
Da(g) = 1
Do(h) = 00
Do(i) = ∞
DV in h:
D₁(a) = ∞
D₁(b) = 00
Dh(c) = 00
Dh(d) = 00
D₁(e) = 1
D₁(f) = 00
Dn(g) = 1
Dm(h) = 0
Dh(i) = 1
De(g)
De(a)
De(i)
De(b)
De(c)
De(f)
De(h)
De(d)
1
at t=1 e receives
DVS from b, d, f, h
8
1
1
compute
1
Q: what is new DV computed in e at
t=1?
-h
Db(a)=8
Db(c) = 1
Do(d) = ∞
Db(e) = 1
1
DV in b:
1
D₂(f) = ∞0
Db(g) = 00
D₁(h) = ∞0
D₂(i) = 00
1
old DV at e
DV in e:
De(a) = ∞
D₂(b) = 1
De(c)
De(d) = 1
De(e) = 0
De(f) = 1
= ∞0
De(g)
De(h) = 1
De(i) = ∞
DV in f:
Di(a) = ∞
D₁(b) = 00
D(c) = 00
Di(d) = ∞
Di(e) = 1
Di(f) = 0
= ∞
Dig)=
Di(h) = 00
D(i) = 1
Transcribed Image Text:DV in d: Dd(a) = 1 Dd(b) = 00 Dd(c) = ∞ Dd(d) = 0 Dale) = 1 Dd(f) = ∞ Da(g) = 1 Do(h) = 00 Do(i) = ∞ DV in h: D₁(a) = ∞ D₁(b) = 00 Dh(c) = 00 Dh(d) = 00 D₁(e) = 1 D₁(f) = 00 Dn(g) = 1 Dm(h) = 0 Dh(i) = 1 De(g) De(a) De(i) De(b) De(c) De(f) De(h) De(d) 1 at t=1 e receives DVS from b, d, f, h 8 1 1 compute 1 Q: what is new DV computed in e at t=1? -h Db(a)=8 Db(c) = 1 Do(d) = ∞ Db(e) = 1 1 DV in b: 1 D₂(f) = ∞0 Db(g) = 00 D₁(h) = ∞0 D₂(i) = 00 1 old DV at e DV in e: De(a) = ∞ D₂(b) = 1 De(c) De(d) = 1 De(e) = 0 De(f) = 1 = ∞0 De(g) De(h) = 1 De(i) = ∞ DV in f: Di(a) = ∞ D₁(b) = 00 D(c) = 00 Di(d) = ∞ Di(e) = 1 Di(f) = 0 = ∞ Dig)= Di(h) = 00 D(i) = 1
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