being pulled by a tow rope attached to a boat. As the driver tle forward, the skier accelerates. A 72kg water skier has an „Om/s. 5.0 seconds later, the speed increases to 11.2m/s. What is e on the water skier? If we assume the efficiency in converting om the boat to the water skier is only 20%, what is the power of is the amount of work done by the resistive force during the

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speed will be v=3.76ms
A water skier is being pulled by a tow rope attached to a boat. As the driver
pushes the throttle forward, the skier accelerates. A 72kg water skier has an
initial speed of 6.0m/s. 5.0 seconds later, the speed increases to 11.2m/s. What is
the net work done on the water skier? If we assume the efficiency in converting
kinetic energy from the boat to the water skier is only 20%, what is the power of
the boat? What is the amount of work done by the resistive force during the
5-second period?
Answer: W =m(v -v)- 3219.84J × 3.2×10°J
net
3219.84J
The power of the boat will be P=-
= 3.2x10 W
0.2x5s
=-3.2×10'W×0.8×5s =-1.3×10ʻJ
resistive
W.
3
Transcribed Image Text:speed will be v=3.76ms A water skier is being pulled by a tow rope attached to a boat. As the driver pushes the throttle forward, the skier accelerates. A 72kg water skier has an initial speed of 6.0m/s. 5.0 seconds later, the speed increases to 11.2m/s. What is the net work done on the water skier? If we assume the efficiency in converting kinetic energy from the boat to the water skier is only 20%, what is the power of the boat? What is the amount of work done by the resistive force during the 5-second period? Answer: W =m(v -v)- 3219.84J × 3.2×10°J net 3219.84J The power of the boat will be P=- = 3.2x10 W 0.2x5s =-3.2×10'W×0.8×5s =-1.3×10ʻJ resistive W. 3
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