Before the furniture store began its ad campaign, it averaged 182 customers per day. The manager is investigating if the average has changed since the ad came out. The data for the 11 randomly selected days since the ad campaign began is shown below: 194, 170, 172, 180, 151, 169, 179, 181, 167, 170, 194 Assuming that the distribution is normal, what can be concluded at the a = 0.01 level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Ho: Hv Select an answer v 182 H1: 182 c. The test statistic ? v = -1.826 (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer v the null hypothesis.

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please help with: d, e ,f, g, h

h. Interpret the p-value in the context of the study.
O If the population mean number of customers since the ad campaign began is 182 and if you
collect data for another 11 days since the ad campaign began, then there would be a
9.78113548% chance that the sample mean for these 11 days would either be less than 175.2 or
greater than 188.8.
There is a 9.78113548% chance that the population mean number of customers since the ad
campaign began is not equal to 182.
O If the population mean number of customers since the ad campaign began is 182 and if you
collect data for another 11 days since the ad campaign began, then there would be a
9.78113548% chance that the population mean would either be less than 175.2 or greater than
188.8.
There is a 9.78113548% chance of a Type I error.
i. Interpret the level of significance in the context of the study.
O If the population mean number of customers since the ad campaign began is different from
182 and if you collect data for another 11 days since the ad campaign began, then there would
be a 1% chance that we would end up falsely concuding that the population mean number of
customers since the ad campaign is equal to 182.
O If the population mean number of customers since the ad campaign began is 182 and if you
collect data for another 11 days since the ad campaign began, then there would be a 1%
chance that we would end up falsely concuding that the population mean number of customers
since the ad campaign began is different from 182.
There is a 1% chance that the population mean number of customers since the ad campaign
began is different from 182.
There is a 1% chance that there will be no customers since everyone shops online nowadays.
Transcribed Image Text:h. Interpret the p-value in the context of the study. O If the population mean number of customers since the ad campaign began is 182 and if you collect data for another 11 days since the ad campaign began, then there would be a 9.78113548% chance that the sample mean for these 11 days would either be less than 175.2 or greater than 188.8. There is a 9.78113548% chance that the population mean number of customers since the ad campaign began is not equal to 182. O If the population mean number of customers since the ad campaign began is 182 and if you collect data for another 11 days since the ad campaign began, then there would be a 9.78113548% chance that the population mean would either be less than 175.2 or greater than 188.8. There is a 9.78113548% chance of a Type I error. i. Interpret the level of significance in the context of the study. O If the population mean number of customers since the ad campaign began is different from 182 and if you collect data for another 11 days since the ad campaign began, then there would be a 1% chance that we would end up falsely concuding that the population mean number of customers since the ad campaign is equal to 182. O If the population mean number of customers since the ad campaign began is 182 and if you collect data for another 11 days since the ad campaign began, then there would be a 1% chance that we would end up falsely concuding that the population mean number of customers since the ad campaign began is different from 182. There is a 1% chance that the population mean number of customers since the ad campaign began is different from 182. There is a 1% chance that there will be no customers since everyone shops online nowadays.
Before the furniture store began its ad campaign, it averaged 182 customers per day. The manager is
investigating if the average has changed since the ad came out. The data for the 11 randomly selected days
since the ad campaign began is shown below:
194, 170, 172, 180, 151, 169, 179, 181, 167, 170, 194
Assuming that the distribution is normal, what can be concluded at the a = 0.01 level of significance?
a. For this study, we should use t-test for a population mean
b. The null and alternative hypotheses would be:
Но:
Select an answer v
182
H1:
182
c. The test statistic ? v = -1.826
(please show your answer to 3 decimal places.)
d. The p-value
(Please show your answer to 4 decimal places.)
%3D
e. The p-value is ? v a
f. Based on this, we should Select an answer v the null hypothesis.
g. Thus, the final conclusion is that ...
O The data suggest that the population mean number of customers since the ad campaign began
is not significantly different from 182 at a = 0.01, so there is insufficient evidence to conclude
that the population mean number of customers since the ad campaign began is different from
182.
The data suggest the populaton mean is significantly different from 182 at a = 0.01, so there
is sufficient evidence to conclude that the population mean number of customers since the ad
campaign began is different from 182.
O The data suggest the population mean is not significantly different from 182 at a = 0.01, so
there is sufficient evidence to conclude that the population mean number of customers since
the ad campaign began is equal to 182.
Transcribed Image Text:Before the furniture store began its ad campaign, it averaged 182 customers per day. The manager is investigating if the average has changed since the ad came out. The data for the 11 randomly selected days since the ad campaign began is shown below: 194, 170, 172, 180, 151, 169, 179, 181, 167, 170, 194 Assuming that the distribution is normal, what can be concluded at the a = 0.01 level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be: Но: Select an answer v 182 H1: 182 c. The test statistic ? v = -1.826 (please show your answer to 3 decimal places.) d. The p-value (Please show your answer to 4 decimal places.) %3D e. The p-value is ? v a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest that the population mean number of customers since the ad campaign began is not significantly different from 182 at a = 0.01, so there is insufficient evidence to conclude that the population mean number of customers since the ad campaign began is different from 182. The data suggest the populaton mean is significantly different from 182 at a = 0.01, so there is sufficient evidence to conclude that the population mean number of customers since the ad campaign began is different from 182. O The data suggest the population mean is not significantly different from 182 at a = 0.01, so there is sufficient evidence to conclude that the population mean number of customers since the ad campaign began is equal to 182.
Expert Solution
Step 1

(a)

 

Determine the type of study.

 

The type of study used t-test for a population mean.

 

(b)

 

State the hypotheses.

Statistics homework question answer, step 1, image 1

That is, there is no evidence to conclude that population mean number of customers since the ad campaign began is different from 182

Statistics homework question answer, step 1, image 2

That is, there is evidence to conclude that population mean number of customers since the ad campaign began is different from 182

Step 2

 

(c)

 

Obtain the value of the test statistic.

 

Use EXCEL Procedure to obtain values for the given samples.

 

Follow the instruction to obtain the value of mean and SD:

 

  1. Open EXCEL
  2. Go to Data>Data Analysis.
  3. Choose Descriptive Statistics.
  4. Enter the input range as $A$1:$A$12.
  5. Check the Labels in the first row.
  6. Check the option Summary statistics
  7. Click OK.

 

EXCEL output:

 

Statistics homework question answer, step 2, image 1

From the EXCEL output, the value of mean is 160.4545 and the standard deviation is 49.1475.

 

The required value is,

Statistics homework question answer, step 2, image 2

Thus, the value of the test statistic is 1.454.

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