double median()//Before calculating the median, we must sort the//array.//If the array is even...if (numbers.size() % 2 -- 0){//Get the mid indexint mid - numbers.size()/ 2;//Get the two numbers in the mid. (mid is the index of the right most middle number.)//Get mid ar'd mid - 1double numl - numbers [mid];double num2 = numbers [mid - 1];//Calculate the average of the two middle numbers and return//the average.return average_mid;else//Determine the median index and return the//number at the median.int mid - numbers.size() /2;return numbers [mid];}//Sorts the array in ascending order.void BubbleSort)for (int i - 0; i < numbers.size(); i++){bool swapped false;for (int j - 0; j< numbers.size() - i - 1; j++{if (numbers[j] > numbers[j + 1]swap(numbers[), numbers[j + 11);swapped - true;if (swapped -- false)return;}private://Used only in Bubble Sort. Ignore...void swap(double& a, double& b){double temp- a;a - b;b - temp;};int main)VCreate a StatSet variable called "s".//Add the number "55" to the StatSet "s".//Calculate the median of the numbers.return 0;PIC CO #include #include using std::cout;using std::vector;class StatSet{private:HCreate a vector of doubles that is called "numbers."public://Nothing to do in the constructor.StatSet()}// Add a new number to the set.vòid add_num(double num){}double mean(){//Sum up the values and return the average.double sum = 0;//Write a loop that would iterate through the vector.sum += numbers[i];return sum / numbers.size();}double median()//Before calculating the median, we must sort the//array.

The given problem is related to C++, where the partially compelete code is given and the requirement…

//Before calculating the median, we must sort the 1/array. //1f the array is even... if (numbers.size() X 2 -- 0) //Get the mid index int mid - numbers.size() / 2; //Get the two numbers in the mid. (mid is the the right most middle number.) //Get mid anid mid- 1. double numl - numbers(mid]; double num2 - numbers(mid - 1]; T/Calculate the average of the two middle num return //the average.

//Before calculating the median, we must sort the 1/array. //1f the array is even... if (numbers.size() X 2 -- 0) //Get the mid index int mid - numbers.size() / 2; //Get the two numbers in the mid. (mid is the the right most middle number.) //Get mid anid mid- 1. double numl - numbers(mid]; double num2 - numbers(mid - 1]; T/Calculate the average of the two middle num return //the average.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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