Before: After: 4) Work Energy Theorem: A two man bobsled has a mass of 390Kg. Starting from rest, the two racers push the sled for the first 50m with a net force of 270N. Neglecting friction what is sled's speed at the end of 50m? V; = 0 Known Find: Strategy: Start with the work energy theorem which is, Work done is equal to change in kinetic energy 390 kg F = 270 N d = 50 m m = V. = 0 m/s W = Kf – Kị Now substitute for Kf and K; and solve the equation for final velocity.
Before: After: 4) Work Energy Theorem: A two man bobsled has a mass of 390Kg. Starting from rest, the two racers push the sled for the first 50m with a net force of 270N. Neglecting friction what is sled's speed at the end of 50m? V; = 0 Known Find: Strategy: Start with the work energy theorem which is, Work done is equal to change in kinetic energy 390 kg F = 270 N d = 50 m m = V. = 0 m/s W = Kf – Kị Now substitute for Kf and K; and solve the equation for final velocity.
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Transcribed Image Text:Before:
After:
4) Work Energy Theorem: A two man
bobsled has a mass of 390Kg. Starting
from rest, the two racers push the
sled for the first 50m with a net force
of 270N. Neglecting friction what is
sled's speed at the end of 50m?
V; = (
Known
Find: v,
Strategy: Start with the work energy
theorem which is, Work done is equal to
change in kinetic energy
m = 390 kg F = 270 N
d = 50 m
V = 0 m/s
W =
K5 – Kị
Now substitute for Kf and K; and solve the equation for final velocity.
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