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Because 2U has a neutron to proton ratio (N/Z ratios) greater than 1, the daughter products will, too. They are called neutron-rich isotopes. a) Calculate the N/Z ratio of 235U b) If one particular product from fission is 1Cs, what is its N/Z ratio? c) Cs is created above the line of stability and will try to get there by undergoing radioactive decay(s). What is the decay sequence of Cs that leads to the stable isotope 1Ce? (Note that 1Ce has a lower N/Z ratio than 1Cs). Show the intermediate products from nuclear decay. 140 140 140 140 140, 140 55CS 140 58Ce

Because 2U has a neutron to proton ratio (N/Z ratios) greater than 1, the daughter products will, too. They are called neutron-rich isotopes. a) Calculate the N/Z ratio of 235U b) If one particular product from fission is 1Cs, what is its N/Z ratio? c) Cs is created above the line of stability and will try to get there by undergoing radioactive decay(s). What is the decay sequence of Cs that leads to the stable isotope 1Ce? (Note that 1Ce has a lower N/Z ratio than 1Cs). Show the intermediate products from nuclear decay. 140 140 140 140 140, 140 55CS 140 58Ce

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235 Because 2U has a neutron to proton ratio (N/Z ratios) greater than 1, the daughter products will, too. They are called neutron-rich isotopes. a) Calculate the N/Z ratio of 235U b) If one particular product from fission is Cs, what is its N/Z ratio? 140 55 140 c) 15Cs is created above the line of stability and will try to get there by undergoing radioactive decay(s). What is the decay sequence of Cs that leads to the stable isotope 1Ce? (Note that 'Ce has a lower N/Z ratio than 1Cs). Show the intermediate products from nuclear decay. 140 140 140 55 140 55 140, 58Ce
Transcribed Image Text:235 Because 2U has a neutron to proton ratio (N/Z ratios) greater than 1, the daughter products will, too. They are called neutron-rich isotopes. a) Calculate the N/Z ratio of 235U b) If one particular product from fission is Cs, what is its N/Z ratio? 140 55 140 c) 15Cs is created above the line of stability and will try to get there by undergoing radioactive decay(s). What is the decay sequence of Cs that leads to the stable isotope 1Ce? (Note that 'Ce has a lower N/Z ratio than 1Cs). Show the intermediate products from nuclear decay. 140 140 140 55 140 55 140, 58Ce
3. Heavy nuclei like 23U can undergo nuclear fission, where they essential split into more or-less equally massive products X and Y. The generic reaction can be written as A → X + Y 200 • Stable isotopes • t12 = 350 years-46 billion years "Island of stability" o 00 0000 180 • tu2 = 12 days-350 years 160 • tu2 =1 second-12 days Radioactive isotopes 12<1 second O Predicted to exist 140 "Sea of instability" 120 100 ----- ------ 80 "Peninsula of stability" 1:1 neutron-to-proton ratio 60 40 "Sea of instability" 20 20 40 60 80 100 120 Number of protons Figure 3 The arrow shows how heavy elements A decay by nuclear fission into daughter products X and Y. Number of neutrons
Transcribed Image Text:3. Heavy nuclei like 23U can undergo nuclear fission, where they essential split into more or-less equally massive products X and Y. The generic reaction can be written as A → X + Y 200 • Stable isotopes • t12 = 350 years-46 billion years "Island of stability" o 00 0000 180 • tu2 = 12 days-350 years 160 • tu2 =1 second-12 days Radioactive isotopes 12<1 second O Predicted to exist 140 "Sea of instability" 120 100 ----- ------ 80 "Peninsula of stability" 1:1 neutron-to-proton ratio 60 40 "Sea of instability" 20 20 40 60 80 100 120 Number of protons Figure 3 The arrow shows how heavy elements A decay by nuclear fission into daughter products X and Y. Number of neutrons
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