Be sure to answer all parts. What is Kp at 1269°C for the reaction 2CO(g) + 02(g) = 2C028) if K, is 2.6 x 1014 at the same temperature?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Chapter 16 (Due 06/10, 23:00)**

**Be sure to answer all parts.**

What is \( K_p \) at 1269°C for the reaction

\[ 2CO(g) + O_2(g) \rightleftharpoons 2CO_2(g) \]

if \( K_c \) is \( 2.6 \times 10^{14} \) at the same temperature?

\[ K_p = \text{ } \boxed{} \times 10^{\boxed{}} \]

(Enter your answer in scientific notation.)

---

This question requires students to determine the equilibrium constant \( K_p \) for the given chemical reaction at a specific temperature, given the equilibrium constant \( K_c \). 

To solve this problem, it's important to understand the relationship between \( K_c \) and \( K_p \) for gases, which is expressed by the equation:

\[ K_p = K_c(RT)^{\Delta n} \]

where \( R \) is the gas constant, \( T \) is the temperature in Kelvin, and \( \Delta n \) is the change in the number of moles of gas (moles of gaseous products minus moles of gaseous reactants).

In this context:
- \( R \) (Gas constant) = 0.0821 L·atm/(K·mol)
- \( T \) (Temperature) = 1269°C, which needs to be converted to Kelvin (T(K) = T(°C) + 273.15).

Once calculated, students should input their answer in the provided format using scientific notation.
Transcribed Image Text:**Chapter 16 (Due 06/10, 23:00)** **Be sure to answer all parts.** What is \( K_p \) at 1269°C for the reaction \[ 2CO(g) + O_2(g) \rightleftharpoons 2CO_2(g) \] if \( K_c \) is \( 2.6 \times 10^{14} \) at the same temperature? \[ K_p = \text{ } \boxed{} \times 10^{\boxed{}} \] (Enter your answer in scientific notation.) --- This question requires students to determine the equilibrium constant \( K_p \) for the given chemical reaction at a specific temperature, given the equilibrium constant \( K_c \). To solve this problem, it's important to understand the relationship between \( K_c \) and \( K_p \) for gases, which is expressed by the equation: \[ K_p = K_c(RT)^{\Delta n} \] where \( R \) is the gas constant, \( T \) is the temperature in Kelvin, and \( \Delta n \) is the change in the number of moles of gas (moles of gaseous products minus moles of gaseous reactants). In this context: - \( R \) (Gas constant) = 0.0821 L·atm/(K·mol) - \( T \) (Temperature) = 1269°C, which needs to be converted to Kelvin (T(K) = T(°C) + 273.15). Once calculated, students should input their answer in the provided format using scientific notation.
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