Be sure to answer all parts. Consider the following Syl reaction. + H₂O What happens to the reaction rate in each of the following instances? Part 1: The leaving group is changed from I to F. The rate decreases Part 2: The solvent is changed from H₂O to CH3NO₂. OH₂ The rate stays the same Part 4: The concentration of H₂O is increased by a factor of five. + I The rate decreases Part 3: The alkyl halide is changed from (CH3)₂C(DCH₂CH3 to (CH₂)₂CHCH (1)CH3- The rate doesn't change ✓ Part 5: The concentrations of both the alkyl halide and H₂O are increased by a factor of five. The rate increases a factor of 5

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### Understanding the SN1 Reaction

**Consider the following SN1 reaction:**

\[ \text{C}_3\text{H}_7\text{I} + \text{H}_2\text{O} \rightarrow \text{C}_3\text{H}_7\text{OH} + \text{I}^- \]

### Reaction Rate Analysis

Analyze the changes in reaction rate under different conditions:

**Part 1:**
- **Condition:** The leaving group is changed from Iodide (I) to Fluoride (F).
- **Result:** The reaction rate **decreases**.
- **Reason:** Iodide is a better leaving group than Fluoride, so the rate is slower when Fluoride is the leaving group.

**Part 2:**
- **Condition:** The solvent is changed from \(\text{H}_2\text{O}\) to \(\text{CH}_3\text{NO}_2\).
- **Result:** The reaction rate **decreases**.
- **Reason:** Water is a protic solvent which stabilizes ions better than aprotic solvents like nitromethane (\(\text{CH}_3\text{NO}_2\)).

**Part 3:**
- **Condition:** The alkyl halide is changed from \((\text{CH}_3)_2\text{C(D}(\text{CH}_2\text{CH}_3))\) to \((\text{CH}_3)_2\text{C(CHCH}(\text{CH}_3))\).
- **Result:** The rate was predicted to **stay the same**, but this was incorrect.
- **Reason:** Changing the structure might affect the stability of the carbocation, potentially altering the rate.

**Part 4:**
- **Condition:** The concentration of \(\text{H}_2\text{O}\) is increased by a factor of five.
- **Result:** The reaction rate **doesn't change**.
- **Reason:** In SN1 reactions, the rate-determining step does not involve the nucleophile concentration, hence, solvent concentration does not affect the rate.

**Part 5:**
- **Condition:** The concentrations of both the alkyl halide and \(\text{H}_2\text{O}\) are increased by a factor of five.
- **Result:** The reaction rate **in
Transcribed Image Text:### Understanding the SN1 Reaction **Consider the following SN1 reaction:** \[ \text{C}_3\text{H}_7\text{I} + \text{H}_2\text{O} \rightarrow \text{C}_3\text{H}_7\text{OH} + \text{I}^- \] ### Reaction Rate Analysis Analyze the changes in reaction rate under different conditions: **Part 1:** - **Condition:** The leaving group is changed from Iodide (I) to Fluoride (F). - **Result:** The reaction rate **decreases**. - **Reason:** Iodide is a better leaving group than Fluoride, so the rate is slower when Fluoride is the leaving group. **Part 2:** - **Condition:** The solvent is changed from \(\text{H}_2\text{O}\) to \(\text{CH}_3\text{NO}_2\). - **Result:** The reaction rate **decreases**. - **Reason:** Water is a protic solvent which stabilizes ions better than aprotic solvents like nitromethane (\(\text{CH}_3\text{NO}_2\)). **Part 3:** - **Condition:** The alkyl halide is changed from \((\text{CH}_3)_2\text{C(D}(\text{CH}_2\text{CH}_3))\) to \((\text{CH}_3)_2\text{C(CHCH}(\text{CH}_3))\). - **Result:** The rate was predicted to **stay the same**, but this was incorrect. - **Reason:** Changing the structure might affect the stability of the carbocation, potentially altering the rate. **Part 4:** - **Condition:** The concentration of \(\text{H}_2\text{O}\) is increased by a factor of five. - **Result:** The reaction rate **doesn't change**. - **Reason:** In SN1 reactions, the rate-determining step does not involve the nucleophile concentration, hence, solvent concentration does not affect the rate. **Part 5:** - **Condition:** The concentrations of both the alkyl halide and \(\text{H}_2\text{O}\) are increased by a factor of five. - **Result:** The reaction rate **in
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