Be sure to answer all parts. Ascorbic acid (vitamin C) contains C, H, and O. In one combustion analysis, 5.24 g of ascorbic acid yields 7.86 g CO, and 2.14 g H,O. Calculate the empirical formula and molecular formula of ascorbic acid given that its molar mass is about 176 g/mol. Add subscripts to complete the formulas. Empirical formula: CHO : Molecular formula: CHO :

Q: When 1.449 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 4.441 grams…

A: The empirical formula represents the smallest number of each element in a compound, which is…

Q: If the sample has a molar mass of 176.0 g/mol, what is the molecular formula of the sample?

A:

Q: The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and…

A: Given : Mass of compound combusted = 2.626 g Mass of CO2 produced = 7.867 g Mass of H2O produced =…

Q: The compound known as butylated hydroxytoluene, abbreviated as BHT, contains carbon, hydrogen, and…

A:

Q: Fructose is a very sweet natural sugar that is present in honey, fruits, and fruit juices. It has a…

A: Given that, %C= 40% %H=6.7% %O=53.3% Molar mass of Fructose=180.1 g mol-1 Then,

Q: An unknown compound is processed using elemental analysis and found to contain 117.4 g of platinum,…

A: We know that,  Number of mole = given mass/molar mass Atomic mass of platinum =195.084 g

Q: Caffeine, a molecule found in coffee, tea, and certain soft drinks, contains C, H, O, and N.…

A: Given, Mass of caffeine = 10.0 g Mass of CO2 = 18.13 g Mass of H2O = 4.639 g Mass of N2 = 2.885 g…

Q: A 14.40 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A:

Q: When 4.510 grams of a hydrocarbon, CHy, wvere burned in a combustion analysis apparatus, 14.15 grams…

A: Whenever the combustion f a hydrocarbon takes place, only carbon dioxide and water vapors are…

Q: The composition of sorbic acid is 64.3% C, 7.2% H and 28.5% O. Since its molecular mass is 112 alb,…

A: Given : Mass % : C=64.3% H=7.2% O= 28.5%

Q: A chemist decomposes samples of several compounds; the masses of their constituent elements are…

A: In order to calculate the empirical formula of each compound , we first need to convert the grams of…

Q: Elemental analysis of a compound with molar mass 214.22 g/mol gives the following mass percent…

A: Given data,Percent of C=72.89%Percent of H=4.71%Percent of O=22.41%Molar mass of…

Q: An unknown compound contains only CC , HH , and OO . Combustion of 9.00 g9.00 g of this compound…

A: The mass of the organic compound is = 9.00 g The mass of carbon dioxide formed is = 20.5 g The molar…

Q: When 6.360 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.50 grams…

A:

Q: Determine the molecular formula of the compound with an empirical formula of CH and a molar mass of…

A: Given:- Determine the molecular formula of the compound with an empirical formula of CH and a molar…

Q: When 4.993 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 15.67 grams…

A:

Q: Catnip's mass composition is 72.3% C, 8.4% H, and 19.3% O). Its molar mass is 166.2 g/mol. Deduce…

A: Empirical Formula :- It is the simplest ratio of number if atoms present in  a molecule.  Molecular…

Q: When 5.347 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 16.38 grams…

A: Empirical formula can be determined from the moles of gases formed of CO2 and H2O

Q: 2.050 g of an unknown sample contains H, S, and O. If the compound contains 0.0500 g H and 0.800 g…

A: Total weight of unknown sample = 2.050g  Mass of H = 0.0500g  Mass of S = 0.800g

Q: What is the molecular formula of a compound if the empirical formula is C,H, and the approximate…

A: Molecular formula: In a molecular formula we describe the number of atoms of all the elements…

Q: A 4.455 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A:

Q: Upon combustion, a compound containing only carbon and hydrogen produces 2.87 g CO2 and 1.57 g H2O.…

A: Empirical formula is way of representing a chemical compound which shows the element present in the…

Q: An unknown compound contains 53.34% rhodium, 9.338% carbon, and the rest is oxygen. a) If you assume…

A: Given a compound with the composition: Rh = 53.34 % C = 9.338 % O = 100 - (53.34 + 9.338) % = 37.322…

Q: Combustion analysis of 1.200 g of an unknown compound containing carbon, hydrogen, and oxygen…

A:

Q: What is the molecular formula of a compound that is composed of 0.186 g C, 0.0390 g H and 0.108 g N…

A: Given: The mass of carbon (C) is 0.186 g The mass of hydrogen (H) is 0.0390 g The mass of nitrogen…

Q: A 7.194 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A: We have to predict the empirical and molecular formula.Given, The mass of organic compound = 7.194…

Q: A 4.600 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis…

A: Empirical formula: An empirical formula is a chemical formula that does not indicate the entire…

Q: A compound with the empirical formula CH2 has a molar mass of 84 g/mol. What is the molecular…

A: * Emperical Formula is the simplest integer ratio of atom present in a compound . It does not tell…

Q: Tartaric acid is the white, powdery substance that coats sour candies such as Sour Patch Kids.…

A:

Q: When 1.717 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 5.805 grams…

A: Answer:The formula in which all the atoms are represented in their simplest integer ratio is called…

Q: A chemist decomposes samples of several compounds; the masses of their constituent elements are…

A: Weight of Co = 0.672g Weight of As = 0.569g Weight of oxygen = 0.486g Atomic weight of Co =…

Q: Some of the formulas could be either molecular or empirical formulas; however, some can only be…

A: empirical formula of a compound gives the simplest ratio of the number of different atoms present,…

Q: Combustion analysis of naphthalene, a hydrocarbon used in mothballs, produces 8.80 g CO2 and 1.44 g…

A: The ratio of the given mass to the molar mass is known as the number of moles. Mathematically,

Q: A scientist is trying to discover information about an unknown metal in a compound. The formula for…

A: Step - 1Formula for the compound = XBr3Means in 1 mol of compound 3 mol of Bromine are…

Q: When 4.876 grams of a hydrocarbon, C,H,, were burned in a combustion analysis apparatus, 15.30 grams…

A:

Q: Chemical formulas can be written as empirical formulas, molecular formulas, or structural formulas.…

A: The solution is given below -

Q: A compound weighs 215 g. It is made up of 120.20 g oxygen, 60.69 g sulfur, and the rest is aluminum.…

A:

Q: A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields…

A:

Q: A 5.899 gram sample of an organic compound containing C, Hand O is analyzed by combustion analysis…

A: Mass of organic sample = 5.899 gMass of CO2 = 12.71 gMass of H2O = 5.204 gmolar mass of given…

Q: What is the empirical formula for a compound that contains 78.2% carbon, 6.57% hydrogen, and 15.2%…

A: we have to find the empirical formula of the compound

Q: What is the empirical formula of the compound?

A: The empirical formula is defined as the lowest whole number ratio of  elements present in a compound

Q: Combustion analysis of a 0.675 g sample of an unknown compound that contains only carbon, hydrogen,…

A: mass of sample = 0.675 gmass of CO2 = 0.627 gmass of H2O = 1.534 gmolar mass of CO2 = 44.01…

Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.