be neutralized by potassium hydroxide [KOH(aq)]. Write a balanced chemical equation for the reaction between these two compounds and identify the salt it produces. For one reaction, 37.5 g of HCN is present initially. How many grams of KOH are needed to neutralize that much HCN?

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Chapter1: Chemical Foundations
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1.) Hydrocyanic acid [HCN(aq)] can be neutralized by potassium hydroxide [KOH(aq)].

  • Write a balanced chemical equation for the reaction between these two compounds and identify the salt it produces.
  • For one reaction, 37.5 g of HCN is present initially. How many grams of KOH are needed to neutralize that much HCN?
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In this question we have to balance the following chemical equation and calculate the grams of KOH required to neutralize the given amount of acid.

SolWe have to balance the chemical equation of neutralization of Hydrocyanic acid HCN(aq) with potassium hydroxide KOH(aq)ReactionHCN(aq) + KOH (aq)  KCN (salt) + H2O (l)   1 mole       1 mole                 1 moleHere, 1 mole of HCN require 1 mole of KOH to formone mole of salt KCN

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