Here's the dataset:BackpackWeightBodyWeightRatioBackProblemsMajorYearSexStatusUnits91250.0721Bio3FemaleU1381950.04102560Philosophy5MaleU12101200.08333331GRC4FemaleU1461550.03870970CSC6MaleG081800.04444440EE2FemaleU1452400.02083330History0MaleG081700.04705880CM3MaleU1541850.02162161ARCE5FemaleU1851300.03846150Bio4FemaleU1421200.01666670Bio5FemaleU881350.05925930Bus3FemaleU15211600.131250ME5MaleU12111700.06470590CPE4MaleU16111700.06470591CPE4MaleU16121250.0961CS3FemaleU12111750.06285710CPE4MaleU16131450.08965521Bio4FemaleU1661050.05714290LS3FemaleU16101250.081LS3FemaleU1751650.0303030Bio3MaleU14201700.1176470CSC2MaleU16141170.1196581EE2FemaleU12111450.07586210CE5MaleU14152050.07317070Bio5FemaleU12102700.0370370AGB3MaleU12181600.11251Mate1MaleU1381500.05333330AGB4MaleU1651400.03571430Poli Sci2FemaleU16251900.1315790Aero Eng.2MaleU1461650.03636361Soc. Sci.1FemaleU15101450.06896551GRC1FemaleU14151200.1251MLL3FemaleU1691350.06666670LS6FemaleG1471450.04827590CPE6MaleU11141650.08484851Math5FemaleU12171450.1172410Psych4FemaleU13141400.10ARCE2FemaleU15111600.068750EE4MaleU1541550.02580650IT3MaleU1681430.05594410Psy2FemaleU1781450.05517241AGB4FemaleU16131350.09629631SOCS3FemaleU16101300.07692310Nut.3FemaleU16151650.09090911Math4FemaleU12101400.07142860LS1FemaleU1451150.04347830Soc. Sci.1FemaleU1361280.0468750Bus1FemaleU1451500.03333330SPC2FemaleU14132200.05909090CE2MaleU13101500.06666670CD3FemaleU16191700.1117650ME5MaleU1281550.05161290Econ2MaleU12211160.1810340Vocal Music4FemaleU16161900.08421050Bus2MaleU14131450.08965520Bio4FemaleU16171440.1180561Bio2FemaleU13101300.07692310Kine2FemaleU1551850.0270271Psych4MaleU1591400.06428570Kine3FemaleU16131250.1040Math2FemaleU17101750.05714290Act.2MaleU19101500.06666670Nutrition4FemaleU12111800.06111111Kine4MaleU1881400.05714291Poli Sci3FemaleU12122200.05454550EE1MaleU14351950.1794870Aero5MaleU12121270.09448821Phys5FemaleU16141500.09333330Kine3FemaleU1621250.0160IT5MaleU1551250.041ARCE2FemaleU1661800.03333330ME4MaleU15201800.1111111CPE1MaleU13141500.09333330Aero2MaleU14141250.1120Pols2FemaleU1781600.050ME2MaleU13251440.1736110LS3FemaleU1721050.01904760IE6FemaleU1581250.0641Pols5FemaleU16151300.1153851Bus3FemaleU16101200.08333330AGB4FemaleU16251750.1428571CE4FemaleU15241450.1655171Bus3FemaleU1651150.04347831ME3FemaleU14101100.09090910CE2FemaleU16191300.1461541LS5FemaleU16131350.09629630LS4FemaleU1691280.07031250Aero1FemaleU16141350.1037040ARCE4MaleU13201700.1176471Bus3MaleU18161750.09142860Bio3MaleU12181500.120IT6MaleU17181600.11251MFGE3MaleU13111680.06547621Bus3MaleU16131550.0838710Psy4MaleU14152100.07142860Arch3MaleU17141650.08484850ME3MaleU1161950.03076920APIO1MaleU16111300.08461540Bus1MaleU1291400.06428570AERO3MaleU12151700.08823530History5MaleU14 To be SubmittedA random sample of 100 high school students in CT is taken. The dataset is in the fileBackpack.xls. Do not print out the data file!1. Find and label the mean, standard deviation, median, minimum and maximum of thevariable Backpack weight.2. Find and label the sample proportion of Backpack weights that are between 10 and 20pounds (include the endpoints).3. Find and interpret a 95% confidence interval for the mean Backpack weight for all CThigh school students.4. Report the error bound.5. Find and interpret a 95% confidence interval for the proportion of all CT high schoolBackpack weights that are between 10 and 20 pounds.6. Report the error bound.7. A researcher claims that the mean weight for all CT high school back pack weights ismore than 12 pounds. Using your answer to #3, comment on this claim and justify.8. A researcher claims that the proportion of all CT high school back pack weights between10 and 20 pounds is more than 45%. Using your answer to #4, comment on this daimand justify.9. Find and label the mean, standard deviation, median, minimum and maximum of thevariable Body weight.10. Find and interpret a 95% confidence interval for the mean Body weight for all CT highschool students.

Name: Here's the dataset:BackpackWeightBodyWeightRatioBackProblemsMajorYearS
Uploaded: 2024-03-05T11:52:21.000Z
Channel: Bartleby
Description: Here's the dataset:BackpackWeightBodyWeightRatioBackProblemsMajorYearSexStatusUnits91250.0721Bio3FemaleU1381950.04102560Philosophy5MaleU12101200.08333331GRC4FemaleU1461550.03870970CSC6MaleG081800.04444440EE2FemaleU1452400.02083330History0MaleG081700.

Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a time so we are answering the first three as you have not mentioned which of these you are looking for. Please re-submit the question separately for the remaining sub-parts. Given : Here we have given a random sample of 100 high school student To find mean, Mean (x)=sum of observations Total number of observations=1166100=11.66 The standard deviation is given by; σ=∑i=1nxi-μNWhere σ=Population standard deviation N=size of the population xi=each value form population μ=mean of the sample σ=3290.44100 =5.7362 To find median we have to set data in ascending order The media is given by , Median =N2=1002=50 th position=11 To find Minimum , Find the lowest value in the backpack weights variable . Minimum=2 To find Maximum , Find the highest value in the backpack weights variable . Minimum=35 Answer : Mean of backpack weights =11.66Standard deviation of backpack weights=5.7362Median of backpack weights=11Minimum of backpack weights=2maximum of backpack weights=35 2) To find the sample proportion of backpack weights that are between 10 and 20 pounds . The total observation that of backpack weights that are between 10 and 20 pounds (including endpoints)=56 Proportion (P)=56100=0.56 Answer : The sample proportion of backpack weights that are between 10 and 20 pounds =0.56 3) To find 95% confidence interval for the mean of backpack weight ,for all CT high school students The confidence interval for mean is given by, Where α=1-0.95=0.05Zα2=Z0.975 =1.96 Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 1.9 0.9713 0.9719 0.9726 0.9732 0.9738 0.9744 0.9750 0.9756 0.9761 0.9767 Confidence interval=x±Zα×σnConfidence interval =(11.66±1.96×5.7362100)Confidence interval =(10.5,12.8) Answer : The 95% confidence interval for the mean of backpack weight ,for all CT high school students =(10.5,12.8)

Answered: be A random sample of 100 high school…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Concept explainers

Topic Video

Question

Here's the dataset:

BackpackWeight	BodyWeight	Ratio	BackProblems	Major	Year	Sex	Status	Units
9	125	0.072	1	Bio	3	Female	U	13
8	195	0.0410256	0	Philosophy	5	Male	U	12
10	120	0.0833333	1	GRC	4	Female	U	14
6	155	0.0387097	0	CSC	6	Male	G	0
8	180	0.0444444	0	EE	2	Female	U	14
5	240	0.0208333	0	History	0	Male	G	0
8	170	0.0470588	0	CM	3	Male	U	15
4	185	0.0216216	1	ARCE	5	Female	U	18
5	130	0.0384615	0	Bio	4	Female	U	14
2	120	0.0166667	0	Bio	5	Female	U	8
8	135	0.0592593	0	Bus	3	Female	U	15
21	160	0.13125	0	ME	5	Male	U	12
11	170	0.0647059	0	CPE	4	Male	U	16
11	170	0.0647059	1	CPE	4	Male	U	16
12	125	0.096	1	CS	3	Female	U	12
11	175	0.0628571	0	CPE	4	Male	U	16
13	145	0.0896552	1	Bio	4	Female	U	16
6	105	0.0571429	0	LS	3	Female	U	16
10	125	0.08	1	LS	3	Female	U	17
5	165	0.030303	0	Bio	3	Male	U	14
20	170	0.117647	0	CSC	2	Male	U	16
14	117	0.119658	1	EE	2	Female	U	12
11	145	0.0758621	0	CE	5	Male	U	14
15	205	0.0731707	0	Bio	5	Female	U	12
10	270	0.037037	0	AGB	3	Male	U	12
18	160	0.1125	1	Mate	1	Male	U	13
8	150	0.0533333	0	AGB	4	Male	U	16
5	140	0.0357143	0	Poli Sci	2	Female	U	16
25	190	0.131579	0	Aero Eng.	2	Male	U	14
6	165	0.0363636	1	Soc. Sci.	1	Female	U	15
10	145	0.0689655	1	GRC	1	Female	U	14
15	120	0.125	1	MLL	3	Female	U	16
9	135	0.0666667	0	LS	6	Female	G	14
7	145	0.0482759	0	CPE	6	Male	U	11
14	165	0.0848485	1	Math	5	Female	U	12
17	145	0.117241	0	Psych	4	Female	U	13
14	140	0.1	0	ARCE	2	Female	U	15
11	160	0.06875	0	EE	4	Male	U	15
4	155	0.0258065	0	IT	3	Male	U	16
8	143	0.0559441	0	Psy	2	Female	U	17
8	145	0.0551724	1	AGB	4	Female	U	16
13	135	0.0962963	1	SOCS	3	Female	U	16
10	130	0.0769231	0	Nut.	3	Female	U	16
15	165	0.0909091	1	Math	4	Female	U	12
10	140	0.0714286	0	LS	1	Female	U	14
5	115	0.0434783	0	Soc. Sci.	1	Female	U	13
6	128	0.046875	0	Bus	1	Female	U	14
5	150	0.0333333	0	SPC	2	Female	U	14
13	220	0.0590909	0	CE	2	Male	U	13
10	150	0.0666667	0	CD	3	Female	U	16
19	170	0.111765	0	ME	5	Male	U	12
8	155	0.0516129	0	Econ	2	Male	U	12
21	116	0.181034	0	Vocal Music	4	Female	U	16
16	190	0.0842105	0	Bus	2	Male	U	14
13	145	0.0896552	0	Bio	4	Female	U	16
17	144	0.118056	1	Bio	2	Female	U	13
10	130	0.0769231	0	Kine	2	Female	U	15
5	185	0.027027	1	Psych	4	Male	U	15
9	140	0.0642857	0	Kine	3	Female	U	16
13	125	0.104	0	Math	2	Female	U	17
10	175	0.0571429	0	Act.	2	Male	U	19
10	150	0.0666667	0	Nutrition	4	Female	U	12
11	180	0.0611111	1	Kine	4	Male	U	18
8	140	0.0571429	1	Poli Sci	3	Female	U	12
12	220	0.0545455	0	EE	1	Male	U	14
35	195	0.179487	0	Aero	5	Male	U	12
12	127	0.0944882	1	Phys	5	Female	U	16
14	150	0.0933333	0	Kine	3	Female	U	16
2	125	0.016	0	IT	5	Male	U	15
5	125	0.04	1	ARCE	2	Female	U	16
6	180	0.0333333	0	ME	4	Male	U	15
20	180	0.111111	1	CPE	1	Male	U	13
14	150	0.0933333	0	Aero	2	Male	U	14
14	125	0.112	0	Pols	2	Female	U	17
8	160	0.05	0	ME	2	Male	U	13
25	144	0.173611	0	LS	3	Female	U	17
2	105	0.0190476	0	IE	6	Female	U	15
8	125	0.064	1	Pols	5	Female	U	16
15	130	0.115385	1	Bus	3	Female	U	16
10	120	0.0833333	0	AGB	4	Female	U	16
25	175	0.142857	1	CE	4	Female	U	15
24	145	0.165517	1	Bus	3	Female	U	16
5	115	0.0434783	1	ME	3	Female	U	14
10	110	0.0909091	0	CE	2	Female	U	16
19	130	0.146154	1	LS	5	Female	U	16
13	135	0.0962963	0	LS	4	Female	U	16
9	128	0.0703125	0	Aero	1	Female	U	16
14	135	0.103704	0	ARCE	4	Male	U	13
20	170	0.117647	1	Bus	3	Male	U	18
16	175	0.0914286	0	Bio	3	Male	U	12
18	150	0.12	0	IT	6	Male	U	17
18	160	0.1125	1	MFGE	3	Male	U	13
11	168	0.0654762	1	Bus	3	Male	U	16
13	155	0.083871	0	Psy	4	Male	U	14
15	210	0.0714286	0	Arch	3	Male	U	17
14	165	0.0848485	0	ME	3	Male	U	11
6	195	0.0307692	0	APIO	1	Male	U	16
11	130	0.0846154	0	Bus	1	Male	U	12
9	140	0.0642857	0	AERO	3	Male	U	12
15	170	0.0882353	0	History	5	Male	U	14

To be Submitted
A random sample of 100 high school students in CT is taken. The dataset is in the file
Backpack.xls. Do not print out the data file!
1. Find and label the mean, standard deviation, median, minimum and maximum of the
variable Backpack weight.
2. Find and label the sample proportion of Backpack weights that are between 10 and 20
pounds (include the endpoints).
3. Find and interpret a 95% confidence interval for the mean Backpack weight for all CT
high school students.
4. Report the error bound.
5. Find and interpret a 95% confidence interval for the proportion of all CT high school
Backpack weights that are between 10 and 20 pounds.
6. Report the error bound.
7. A researcher claims that the mean weight for all CT high school back pack weights is
more than 12 pounds. Using your answer to #3, comment on this claim and justify.
8. A researcher claims that the proportion of all CT high school back pack weights between
10 and 20 pounds is more than 45%. Using your answer to #4, comment on this daim
and justify.
9. Find and label the mean, standard deviation, median, minimum and maximum of the
variable Body weight.
10. Find and interpret a 95% confidence interval for the mean Body weight for all CT high
school students.

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 4 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Application of Algebra$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.