BC:3.1 For the discrete time function f[n] (0.6)-1 sin (n +90°) u[n+3] a.) Sketch (by hand) the waveform for f[n] vs n. Label the value of the signal for the first 5 nonzero samples. b.) Sketch the waveform, x[n] = 10f[n] (u[n+ 5] - u[n - 4]) vs n. Label the values of a[n] for samples where -6 ≤ n ≤ 5. c.) Sketch the waveform for g[n] = f[n+ 1] vs n. Label the value of the signal, g[n], for the first 5 nonzero samples. d.) Sketch the waveform for a[n] = f[n - 3] vs n. Label the value of the signal, a[n], for the first 5 nonzero samples. e.) Sketch the waveform for 3[n] = f[5-n] vs n. Label the value of the signal, B[n], for the last 5 nonzero samples.

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Please answer only parts D and E
BC:3.1 For the discrete time function
f[n] (0.6)-¹ sin (n +90°). u[n+3]
VS
a.) Sketch (by hand) the waveform for f[n]
n. Label the value of the signal for the first
5 nonzero samples.
b.) Sketch the waveform,
x[n] = 10f[n] (u[n+ 5] - u[n −4])
vs n. Label the values of x[n] for samples where
-6 ≤ n ≤ 5.
c.) Sketch the waveform for g[n] = f[n+ 1] vs n.
Label the value of the signal, g[n], for the first
5 nonzero samples.
d.) Sketch the waveform for a[n] = f[n - 3] vs n.
Label the value of the signal, a[n], for the first
5 nonzero samples.
e.) Sketch the waveform for 3[n] = f[5-n] vs n.
Label the value of the signal, 3[n], for the last
5 nonzero samples.
Transcribed Image Text:BC:3.1 For the discrete time function f[n] (0.6)-¹ sin (n +90°). u[n+3] VS a.) Sketch (by hand) the waveform for f[n] n. Label the value of the signal for the first 5 nonzero samples. b.) Sketch the waveform, x[n] = 10f[n] (u[n+ 5] - u[n −4]) vs n. Label the values of x[n] for samples where -6 ≤ n ≤ 5. c.) Sketch the waveform for g[n] = f[n+ 1] vs n. Label the value of the signal, g[n], for the first 5 nonzero samples. d.) Sketch the waveform for a[n] = f[n - 3] vs n. Label the value of the signal, a[n], for the first 5 nonzero samples. e.) Sketch the waveform for 3[n] = f[5-n] vs n. Label the value of the signal, 3[n], for the last 5 nonzero samples.
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