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BASIC STOICHIOMETRY TO1/S11 Based on the balanced equation, Molar Mass (g/mol) LiH + H,0 - LIOH + H2 LIH 7.949 calculate the molecules of H,0 required when 98 formula units of LIOH are formed. Н2о 18.015 LIOH 23.948 Н2 Avogadro's No. 6.022x1023 mol*1 2.016 exact number, no tolerance LIMITING REAGENTS T02/S12 Based on the balanced equation Molar Mass (g/mol) 21205 + 10NO - 5N204 + 212 I205 333.80 calculate the number of excess reagent units remaining when 68 I,05 molecules and 330 NO molecules react? 30.006 NO N204 I2 Avogadro's No. 6.022x1023 mol"1 92.011 253.8 exact number, no tolerance

BASIC STOICHIOMETRY TO1/S11 Based on the balanced equation, Molar Mass (g/mol) LiH + H,0 - LIOH + H2 LIH 7.949 calculate the molecules of H,0 required when 98 formula units of LIOH are formed. Н2о 18.015 LIOH 23.948 Н2 Avogadro's No. 6.022x1023 mol*1 2.016 exact number, no tolerance LIMITING REAGENTS T02/S12 Based on the balanced equation Molar Mass (g/mol) 21205 + 10NO - 5N204 + 212 I205 333.80 calculate the number of excess reagent units remaining when 68 I,05 molecules and 330 NO molecules react? 30.006 NO N204 I2 Avogadro's No. 6.022x1023 mol"1 92.011 253.8 exact number, no tolerance

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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BASIC STOICHIOMETRY TO1/S11 Based on the balanced equation, Molar Mass (g/mol) LiH + H,0 - LIOH + H2 LIH 7.949 calculate the molecules of H,0 required when 98 formula units of LIOH are formed. Н2о 18.015 LIOH 23.948 Н2 Avogadro's No. 6.022x1023 mol*1 2.016 exact number, no tolerance
Transcribed Image Text:BASIC STOICHIOMETRY TO1/S11 Based on the balanced equation, Molar Mass (g/mol) LiH + H,0 - LIOH + H2 LIH 7.949 calculate the molecules of H,0 required when 98 formula units of LIOH are formed. Н2о 18.015 LIOH 23.948 Н2 Avogadro's No. 6.022x1023 mol*1 2.016 exact number, no tolerance
LIMITING REAGENTS T02/S12 Based on the balanced equation Molar Mass (g/mol) 21205 + 10NO - 5N204 + 212 I205 333.80 calculate the number of excess reagent units remaining when 68 I,05 molecules and 330 NO molecules react? 30.006 NO N204 I2 Avogadro's No. 6.022x1023 mol"1 92.011 253.8 exact number, no tolerance
Transcribed Image Text:LIMITING REAGENTS T02/S12 Based on the balanced equation Molar Mass (g/mol) 21205 + 10NO - 5N204 + 212 I205 333.80 calculate the number of excess reagent units remaining when 68 I,05 molecules and 330 NO molecules react? 30.006 NO N204 I2 Avogadro's No. 6.022x1023 mol"1 92.011 253.8 exact number, no tolerance
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