BASIC STOICHIOMETRY TO1/S11 Based on the balanced equation, Molar Mass (g/mol) LiH + H,0 - LIOH + H2 LIH 7.949 calculate the molecules of H,0 required when 98 formula units of LIOH are formed. Н2о 18.015 LIOH 23.948 Н2 Avogadro's No. 6.022x1023 mol*1 2.016 exact number, no tolerance LIMITING REAGENTS T02/S12 Based on the balanced equation Molar Mass (g/mol) 21205 + 10NO - 5N204 + 212 I205 333.80 calculate the number of excess reagent units remaining when 68 I,05 molecules and 330 NO molecules react? 30.006 NO N204 I2 Avogadro's No. 6.022x1023 mol"1 92.011 253.8 exact number, no tolerance

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BASIC STOICHIOMETRY TO1/S11
Based on the balanced equation,
Molar Mass (g/mol)
LiH + H,0 - LIOH + H2
LIH
7.949
calculate the molecules of H,0 required when 98 formula units of LIOH are formed.
Н2о
18.015
LIOH
23.948
Н2
Avogadro's No.
6.022x1023 mol*1
2.016
exact number, no tolerance
Transcribed Image Text:BASIC STOICHIOMETRY TO1/S11 Based on the balanced equation, Molar Mass (g/mol) LiH + H,0 - LIOH + H2 LIH 7.949 calculate the molecules of H,0 required when 98 formula units of LIOH are formed. Н2о 18.015 LIOH 23.948 Н2 Avogadro's No. 6.022x1023 mol*1 2.016 exact number, no tolerance
LIMITING REAGENTS T02/S12
Based on the balanced equation
Molar Mass (g/mol)
21205 + 10NO - 5N204 + 212
I205
333.80
calculate the number of excess reagent units remaining when 68 I,05 molecules and 330 NO molecules react?
30.006
NO
N204
I2
Avogadro's No.
6.022x1023 mol"1
92.011
253.8
exact number, no tolerance
Transcribed Image Text:LIMITING REAGENTS T02/S12 Based on the balanced equation Molar Mass (g/mol) 21205 + 10NO - 5N204 + 212 I205 333.80 calculate the number of excess reagent units remaining when 68 I,05 molecules and 330 NO molecules react? 30.006 NO N204 I2 Avogadro's No. 6.022x1023 mol"1 92.011 253.8 exact number, no tolerance
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