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Basic solution Potassium permanganate, KMNO4, is a powerful oxidizing agent. The products of a given redox reaction with the permanganate ion depend on the reaction conditions used. In basic solution, the following equation represents the reaction of this ion with a solution containing sodium fluoride: MnO4 (aq) +F (aq)→MnO2 (s) + F2 (aq) Since this reaction takes place in basic solution, H2O(1) and OH (aq) will be shown in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation: MnO4 (aq)+ F (aq) +_→MnO2 (s) + F2 (aq) + Part B What are the coefficients of the reactants and products in the balanced equation above? Remember to include H2O(1) and OH-(aq) in the blanks where appropriate. Your answer should have six terms. Enter the equation coefficients in order separated by commas (e.g., 2,2,1,4,4,3). Include coefficients of 1, as required, for grading purposes. View Available Hint(s) Submit Request Answer

Basic solution Potassium permanganate, KMNO4, is a powerful oxidizing agent. The products of a given redox reaction with the permanganate ion depend on the reaction conditions used. In basic solution, the following equation represents the reaction of this ion with a solution containing sodium fluoride: MnO4 (aq) +F (aq)→MnO2 (s) + F2 (aq) Since this reaction takes place in basic solution, H2O(1) and OH (aq) will be shown in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation: MnO4 (aq)+ F (aq) +_→MnO2 (s) + F2 (aq) + Part B What are the coefficients of the reactants and products in the balanced equation above? Remember to include H2O(1) and OH-(aq) in the blanks where appropriate. Your answer should have six terms. Enter the equation coefficients in order separated by commas (e.g., 2,2,1,4,4,3). Include coefficients of 1, as required, for grading purposes. View Available Hint(s) Submit Request Answer

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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13:24 Tue May 4 Done < AA A session.masteringchemistry.com <Problem Set #9 (Ch 19) Adaptive Follow-Up Balancing Redox Equations: Half-reaction Method Item 4 I Review I Constants I Periodic Table In addition to mass balance, oxidation-reduction Notice that coefficients of 1 are excluded from the final balanced equation. reactions must be balanced such that the number of electrons lost in the oxidation equals the number of electrons gained in the reduction. This balancing can be done by two methods: the half-reaction Basic solution method or the oxidation number method. The half- Potassium permanganate, KMnO4, is a powerful oxidizing agent. The products of a given redox reaction with the permanganate ion depend on the reaction conditions used. In basic solution, the following equation represents the reaction of this ion with a solution containing sodium fluoride: reaction method balances the electrons lost in the oxidation half-reaction with the electrons gained in the reduction half-reaction. In either method H2O(1), OH-(aq), and H+ (aq) may be added MnO4¯(aq) + F- (aq)→MnO2(s) +F2(aq) to complete the mass balance. Which substances are used depends on the reaction conditions. Since this reaction takes place in basic solution, H20(1) and OH (aq) will be shown in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation: MnO4 (aq) + F (aq) + →MNO2 (s) + F2(aq) + Part B What are the coefficients of the reactants and products in the balanced equation above? Remember to include H2O(1) and OH (aq) in the blanks where appropriate. Your answer should have six terms. Enter the equation coefficients in order separated by commas (e.g., 2,2,1,4,4,3). Include coefficients of 1, as required, for grading purposes. View Available Hint(s) Submit Request Answer Provide Feedback Next >
Transcribed Image Text:13:24 Tue May 4 Done < AA A session.masteringchemistry.com <Problem Set #9 (Ch 19) Adaptive Follow-Up Balancing Redox Equations: Half-reaction Method Item 4 I Review I Constants I Periodic Table In addition to mass balance, oxidation-reduction Notice that coefficients of 1 are excluded from the final balanced equation. reactions must be balanced such that the number of electrons lost in the oxidation equals the number of electrons gained in the reduction. This balancing can be done by two methods: the half-reaction Basic solution method or the oxidation number method. The half- Potassium permanganate, KMnO4, is a powerful oxidizing agent. The products of a given redox reaction with the permanganate ion depend on the reaction conditions used. In basic solution, the following equation represents the reaction of this ion with a solution containing sodium fluoride: reaction method balances the electrons lost in the oxidation half-reaction with the electrons gained in the reduction half-reaction. In either method H2O(1), OH-(aq), and H+ (aq) may be added MnO4¯(aq) + F- (aq)→MnO2(s) +F2(aq) to complete the mass balance. Which substances are used depends on the reaction conditions. Since this reaction takes place in basic solution, H20(1) and OH (aq) will be shown in the reaction. Places for these species are indicated by the blanks in the following restatement of the equation: MnO4 (aq) + F (aq) + →MNO2 (s) + F2(aq) + Part B What are the coefficients of the reactants and products in the balanced equation above? Remember to include H2O(1) and OH (aq) in the blanks where appropriate. Your answer should have six terms. Enter the equation coefficients in order separated by commas (e.g., 2,2,1,4,4,3). Include coefficients of 1, as required, for grading purposes. View Available Hint(s) Submit Request Answer Provide Feedback Next >
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