Last table and questions thanks Experiment Electrical Equivalent of HeatIf there are no energy losses to the surroundings, all the electric energy given off by the resistor shouldbe absorbed by the water. The electric energy, E, dissipated by the resistor isE = Ptwhere t is the time during which the current flows through the resistor and P is the electric powerdeterminedasP = IVwhere I is the current through the resistor and V is the voltage across the resistor. If the current ismeasured in amperes, the voltage is measured in volts, and the time is measured in seconds thecalculated electric energy E is measured in joules.The thermal energy, Q, gained by the water is determined asQ = CMATwhere m is the mass of the water, c is the specific heat of water (1 cal/g °C), and AT is the changeof thewatertemperature. If the mass is measured in grams and temperature is measured Celsius degrees thecalculated thermal energy Qis measured in calories.It follows from the law of conservation of energy thatE(joules) = Q(calories)The last equation allows us to find how many joules are equivalent to 1 calorie or the so-called electricalequivalent of heat (E.E.H.) asE joules)Q(calories)Е.Е.Н.This number establishes very important relationship between two different units used to measure theenergy: joules and calories.Accepted value for this relationship is1cal = 4.184J1. Find the mass of water in grams as m = pv where vis the water volume (in ml) andp = 1 g/mL is the water density.2. Recordthe initial water temperature7T; .3. Click on the Power switch to turn it on and heat the water until its temperatureincreases by approximately 10C°. Record the voltage V and the current I.4. Turn the Power switch off and record the final water temperature T, and the time of theexperiment t. 5. Calculate the electric energy E and the thermal energy Q and find your experimentalvalue of E.E.H.6. Enter all your data and the results of calculations in the data tables below.ItemAmountItemAmountItemAmountWater Vol. v315mlInitial temp. T;12VoltageV82315gFinal temp. T23CurrentiWater mass mTemp. change AT11PowerP492Timet35sItemAmountElectrical Energy, E = Pt17220Thermal Energy, Q = cmATElectrical Equivalent of HeatElectricalEnergyE.E.H =Thermal EnergyQuestions:Based on yourdata, what is the resistance of the resistor used in this virtual experiment?In this experiment, it was assumed that all dissipated electric energy was absorbed by the waterand converted into the thermal energy of water. If part of the electric energy was lost intosurroundings (heating, for example, the air in the room and the beaker) will your experimentalvalue of E.E.H. increase, decrease, or stay the same?

Answered: Image /qna-images/answer/45968b1f-4b3f-4668-82cc-76d19e50913b.jpg

Based on your data, what is the resistance of the resistor used in this virtual experiment? In this experiment, it was assumed that all dissipatedelectric energy was absorbed by the water and converted into the thermal energy of water. If part of the electric energy was lost into surroundings (heating, for example, the air in the room and the beaker) will your experimental value of E.E.H. increase, decrease, or stay the same?

Based on your data, what is the resistance of the resistor used in this virtual experiment? In this experiment, it was assumed that all dissipatedelectric energy was absorbed by the water and converted into the thermal energy of water. If part of the electric energy was lost into surroundings (heating, for example, the air in the room and the beaker) will your experimental value of E.E.H. increase, decrease, or stay the same?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

Last table and questions thanks

Experiment Electrical Equivalent of Heat
If there are no energy losses to the surroundings, all the electric energy given off by the resistor should
be absorbed by the water. The electric energy, E, dissipated by the resistor is
E = Pt
where t is the time during which the current flows through the resistor and P is the electric power
determinedas
P = IV
where I is the current through the resistor and V is the voltage across the resistor. If the current is
measured in amperes, the voltage is measured in volts, and the time is measured in seconds the
calculated electric energy E is measured in joules.
The thermal energy, Q, gained by the water is determined as
Q = CMAT
where m is the mass of the water, c is the specific heat of water (1 cal/g °C), and AT is the changeof the
watertemperature. If the mass is measured in grams and temperature is measured Celsius degrees the
calculated thermal energy Qis measured in calories.
It follows from the law of conservation of energy that
E(joules) = Q(calories)
The last equation allows us to find how many joules are equivalent to 1 calorie or the so-called electrical
equivalent of heat (E.E.H.) as
E joules)
Q(calories)
Е.Е.Н.
This number establishes very important relationship between two different units used to measure the
energy: joules and calories.
Accepted value for this relationship is
1cal = 4.184J
1. Find the mass of water in grams as m = pv where vis the water volume (in ml) and
p = 1 g/mL is the water density.
2. Recordthe initial water temperature7T; .
3. Click on the Power switch to turn it on and heat the water until its temperature
increases by approximately 10C°. Record the voltage V and the current I.
4. Turn the Power switch off and record the final water temperature T, and the time of the
experiment t.

5. Calculate the electric energy E and the thermal energy Q and find your experimental
value of E.E.H.
6. Enter all your data and the results of calculations in the data tables below.
Item
Amount
Item
Amount
Item
Amount
Water Vol. v
315ml
Initial temp. T;
12
VoltageV
82
315g
Final temp. T
23
Currenti
Water mass m
Temp. change AT
11
PowerP
492
Timet
35s
Item
Amount
Electrical Energy, E = Pt
17220
Thermal Energy, Q = cmAT
Electrical Equivalent of Heat
ElectricalEnergy
E.E.H =
Thermal Energy
Questions:
Based on yourdata, what is the resistance of the resistor used in this virtual experiment?
In this experiment, it was assumed that all dissipated electric energy was absorbed by the water
and converted into the thermal energy of water. If part of the electric energy was lost into
surroundings (heating, for example, the air in the room and the beaker) will your experimental
value of E.E.H. increase, decrease, or stay the same?

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