**Problem Statement:**Based on the partial reaction mechanism shown below and the reaction details, which of the following is the expected product of this reaction?**Reaction Mechanism:**The mechanism begins with a hydroxonium ion (H₃O⁺) where the oxygen donates a lone pair to a carbon in the alkene chain, forming a carbocation intermediate. A subsequent step involves the addition of water (H₂O).**Answer Choices:**1. **Choice A:** 3-buten-1-ol Structure: A four-carbon chain with an alcohol group (OH) attached at the terminal carbon.2. **Choice B:** 2-buten-1-ol Structure: A carbocation intermediate is shown with a positive charge on oxygen, forming a five-membered ring.3. **Choice C:** 2-penten-2-ol Structure: An alcohol group (OH) attached to the second carbon of a five-carbon chain with a double bond.4. **Choice D:** 4-penten-1-ol methyl ether Structure: A five-carbon chain with an ether group (OCH₃) at the terminal end.5. **Choice E:** 2-penten-1-ol Structure: A five-carbon chain with an alcohol group (OH) attached at the terminal carbon.**Explanation of Diagrams:**The diagrams represent different organic structures that could potentially be products of the reaction. Each structure contains a different placement or form of functional groups such as alcohols and ethers, and one includes a resonance-stabilized carbocation. The choice of the correct product will depend on understanding the mechanism and stability of intermediates.

This reaction proceeds via proton abstraction of hydroxide ion followed by epoxide ring opening. In this reaction, the following reaction occurs : At first, the hydroxide ion, OH- takes the proton. TThe negative charge generated is delocalized. The epoxide ring opens and a negative charge is generated on oxygen. Then the oxygen abstracts proton from water with the negative charge. The mechanism is shown below :.. Thus, the correct option is : Option 5