Based on the following values: Mathematical expectation: E(X) = ∑Xn1 = 1204 = 30 E(Y) = ∑Yn2 = 1884 = 47 E(Z) = ∑Zn3 = 1784 = 44.5 Variance: var(X) = 1n1-1∑X2-1n∑X2 = 14-13678-12024 =26 var(Y) = 1n2-1∑Y2-1n∑Y2 = 14-18890-18824 =18 var(Z) = 1n3-1∑Z2-1n3∑Z2 = 14-18322-17824 =133.6667 Root mean square deviation sd(X)= var(X) =26 = 5.0990 sd(Y)= var(Y) =18 = 4.2426 sd(Z)= var(Z) =133.6667 = 11.5614 Correlation coefficients X Y Z 25 44 28 28 43 48 37 49 55 30 52 47 1. Expectation 120 188 178 2. Variance 26 18 133.6667 3. root mean square deviation 5.099 4.2426 11.5614 Check the hypothesis in the image below. The tablic values are also there
Based on the following values: Mathematical expectation: E(X) = ∑Xn1 = 1204 = 30 E(Y) = ∑Yn2 = 1884 = 47 E(Z) = ∑Zn3 = 1784 = 44.5 Variance: var(X) = 1n1-1∑X2-1n∑X2 = 14-13678-12024 =26 var(Y) = 1n2-1∑Y2-1n∑Y2 = 14-18890-18824 =18 var(Z) = 1n3-1∑Z2-1n3∑Z2 = 14-18322-17824 =133.6667 Root mean square deviation sd(X)= var(X) =26 = 5.0990 sd(Y)= var(Y) =18 = 4.2426 sd(Z)= var(Z) =133.6667 = 11.5614 Correlation coefficients X Y Z 25 44 28 28 43 48 37 49 55 30 52 47 1. Expectation 120 188 178 2. Variance 26 18 133.6667 3. root mean square deviation 5.099 4.2426 11.5614 Check the hypothesis in the image below. The tablic values are also there
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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Question
Based on the following values:
Mathematical expectation:
E(X) = ∑Xn1 = 1204 = 30
E(Y) = ∑Yn2 = 1884 = 47
E(Z) = ∑Zn3 = 1784 = 44.5
Variance:
var(X) = 1n1-1∑X2-1n∑X2 = 14-13678-12024 =26
var(Y) = 1n2-1∑Y2-1n∑Y2 = 14-18890-18824 =18
var(Z) = 1n3-1∑Z2-1n3∑Z2 = 14-18322-17824 =133.6667
Root mean square deviation
sd(X)= var(X) =26 = 5.0990
sd(Y)= var(Y) =18 = 4.2426
sd(Z)= var(Z) =133.6667 = 11.5614
|
Y |
Z |
|
|
25 |
44 |
28 |
|
28 |
43 |
48 |
|
37 |
49 |
55 |
|
30 |
52 |
47 |
1. Expectation |
120 |
188 |
178 |
2. Variance |
26 |
18 |
133.6667 |
3. root mean square deviation |
5.099 |
4.2426 |
11.5614 |
Check the hypothesis in the image below. The tablic values are also there

Transcribed Image Text:α = 0.05
T(a/2, v = 2) = 4.3027
T(a/2, v = 3) = 3.1825
T(a/2, v = 4) = 2.7765
T(a/2, v = 6) = 2.4469
F(a/2, 4, 4) = 9.6045
F(a/2,3,3)= 15.4392
F(a/2,3,4)= 9.9792
F(a/2, 1,4)= 7.708
F(a/2, 4, 3) = 9.12
G(a,3,3): = 0.7977
x² = x²(2,3)= 0.2158
x² = x² (1-2, 3) =
T(α, 4) = 1.71
= 9.348
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Transcribed Image Text:Ho: m, 44; H₁: my # 44
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