Based on the following values: Mathematical expectation: E(X) = ∑Xn1 = 1204 = 30 E(Y) = ∑Yn2 = 1884 = 47 E(Z) = ∑Zn3 = 1784 = 44.5 Variance: var(X) = 1n1-1∑X2-1n∑X2 = 14-13678-12024 =26 var(Y) = 1n2-1∑Y2-1n∑Y2 = 14-18890-18824 =18 var(Z) = 1n3-1∑Z2-1n3∑Z2 = 14-18322-17824 =133.6667 Root mean square deviation sd(X)= var(X) =26 = 5.0990 sd(Y)= var(Y) =18 = 4.2426 sd(Z)= var(Z) =133.6667 = 11.5614 Correlation coefficients X Y Z 25 44 28 28 43 48 37 49 55 30 52 47 1. Expectation 120 188 178 2. Variance 26 18 133.6667 3. root mean square deviation 5.099 4.2426 11.5614 Check the hypotheses in the image below, in accordance with the tablic values.
Based on the following values: Mathematical expectation: E(X) = ∑Xn1 = 1204 = 30 E(Y) = ∑Yn2 = 1884 = 47 E(Z) = ∑Zn3 = 1784 = 44.5 Variance: var(X) = 1n1-1∑X2-1n∑X2 = 14-13678-12024 =26 var(Y) = 1n2-1∑Y2-1n∑Y2 = 14-18890-18824 =18 var(Z) = 1n3-1∑Z2-1n3∑Z2 = 14-18322-17824 =133.6667 Root mean square deviation sd(X)= var(X) =26 = 5.0990 sd(Y)= var(Y) =18 = 4.2426 sd(Z)= var(Z) =133.6667 = 11.5614 Correlation coefficients X Y Z 25 44 28 28 43 48 37 49 55 30 52 47 1. Expectation 120 188 178 2. Variance 26 18 133.6667 3. root mean square deviation 5.099 4.2426 11.5614 Check the hypotheses in the image below, in accordance with the tablic values.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Based on the following values:
Mathematical expectation:
E(X) = ∑Xn1 = 1204 = 30
E(Y) = ∑Yn2 = 1884 = 47
E(Z) = ∑Zn3 = 1784 = 44.5
Variance:
var(X) = 1n1-1∑X2-1n∑X2 = 14-13678-12024 =26
var(Y) = 1n2-1∑Y2-1n∑Y2 = 14-18890-18824 =18
var(Z) = 1n3-1∑Z2-1n3∑Z2 = 14-18322-17824 =133.6667
Root
sd(X)= var(X) =26 = 5.0990
sd(Y)= var(Y) =18 = 4.2426
sd(Z)= var(Z) =133.6667 = 11.5614
|
Y |
Z |
|
|
25 |
44 |
28 |
|
28 |
43 |
48 |
|
37 |
49 |
55 |
|
30 |
52 |
47 |
1. Expectation |
120 |
188 |
178 |
2. Variance |
26 |
18 |
133.6667 |
3. root mean square deviation |
5.099 |
4.2426 |
11.5614 |
Check the hypotheses in the image below, in accordance with the tablic values.

Transcribed Image Text:α = 0.05
T(a/2, v = 2) = 4.3027
T(a/2, v = 3) = 3.1825
T(a/2, v = 4) = 2.7765
T(a/2, v = 6) = 2.4469
F(a/2, 4, 4) = 9.6045
F(a/2,3,3)= 15.4392
F(a/2,3,4)= 9.9792
F(a/2, 1,4)= 7.708
F(a/2, 4, 3) = 9.12
G(a,3,3): = 0.7977
x² = x²(2,3)= 0.2158
x² = x² (1-2, 3) =
T(α, 4) = 1.71
= 9.348

Transcribed Image Text:Ho: 02 = 03: H1:03 + 0
осии
Ho: 03 = 02;
H1: 02 +02
сии
Ho: 0 = 02; H1:02 + 02
#
o
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Thank you, could you please test the two hypotheses below as well?
Thanks,

Transcribed Image Text:4.Verification of hypothesis of uniformity of many variances
Họ: đải = đẳz = đẳs; H: Gải toả + đảo
5. Testing a hypothesis that the mathematical expectation is equal to a given constant
HO: mx = 31; H1: mx # 31
|
Solution
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