Based on the following information, please draw a functional electrochemical cell, labelling all components & ingredients, as well as identifying the cathode & anode, and which side is the reduction & oxidation reaction. Half reaction A: Hg2+ + 2e- ↔ Hg Half reaction B: Hg + 2 OH- ↔ HgO + H2O + 2e- Overall reaction: HgO + H2O ↔ Hg2+ + 2 OH-
Based on the following information, please draw a functional electrochemical cell, labelling all components & ingredients, as well as identifying the cathode & anode, and which side is the reduction & oxidation reaction. Half reaction A: Hg2+ + 2e- ↔ Hg Half reaction B: Hg + 2 OH- ↔ HgO + H2O + 2e- Overall reaction: HgO + H2O ↔ Hg2+ + 2 OH-
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 16E: Balance the following reactions and write the reactions using cell notation. Ignore any inert...
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- Based on the following information, please draw a functional
electrochemical cell, labelling all components & ingredients, as well as identifying the cathode & anode, and which side is the reduction & oxidation reaction.
Half reaction A: Hg2+ + 2e- ↔ Hg
Half reaction B: Hg + 2 OH- ↔ HgO + H2O + 2e-
Overall reaction: HgO + H2O ↔ Hg2+ + 2 OH-
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