Based on the following domain model class diagram, answer the followings: 1) How many accounts can a customer have? 2) How many branches can a customer be assigned to? 3) How many customers can a branch have? 4) What attributes can you use for keys? Customer Account Branch custNumber (key) fulName billAddress homePhone officePhone account ID key) branchID (key) managerName branchLocation mainPhone accountType 1 1. 0. 1 dateOpened balance Transaction transID (key) transDate transType transAmount

Based on the following domain model class diagram, answer the followings: 1) How many accounts can a customer have? 2) How many branches can a customer be assigned to? 3) How many customers can a branch have? 4) What attributes can you use for keys? Customer Account Branch custNumber (key) fulName billAddress homePhone officePhone account ID key) branchID (key) managerName branchLocation mainPhone accountType 1 1. 0. 1 dateOpened balance Transaction transID (key) transDate transType transAmount

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

What are domain constraints?
Please type it and follow the format given in the second picture. thank you
Part 1: Use the following schema to answer the questions 1-3 below. This schema refers to a gaming organization. There can be any number of players per game. Each game and each tournament has one winner; if the game or tournament is ongoing, the winner is null. The gameWinner and tournamentWinner attributes are foreign keys for memberID. Member (memberlD, memberName, joinDate) Game (gamelD, gameType, gameDate, gameWinner, tournamentName) MemberGame (memberlD, gamelD) Tournament (tournamentName, tournamentWinner) 1. Write a description of what each of the following queries does: a. SELECT memberID, gamelD FROM Member NATURAL JOIN MemberGame NATURAL JOIN Game WHERE joinDate = "2021-01-01" b. Write two functionally different relational algebra statements equivalent to the query in 1a. C. Which of your answers to question 3 will most likely be processed faster? Justify your answer.
For the table BOOKAUTHOR below you are given the following functional dependencies. BOOKAUTHOR (ISBN, BookTitle, Author_Num, LastName, Publisher, Royalty, Edition) Functional dependencies: 1. ISBN BookTitle, Publisher, Edition 2. Author Num → LastName 3. BookTitle → Publisher 4. {ISBN, Author_Num} → BookTitle, LastName, Publisher, Royalty, Edition Write the types of functional dependencies shown in (1) to (4) above. Also, decompose the table to the third normal from (3NF).
Part 1: Use the following schema to answer the questions 1-3 below. This schema refers to a gaming organization. There can be any number of players per game. Each game and each tournament has one winner; if the game or tournament is ongoing, the winner is null. The gameWinner and tournamentWinner attributes are foreign keys for memberID. Member (memberlD, memberName, joinDate) Game (gamelD, gameType, gameDate, gameWinner, tournamentName) MemberGame (memberlD, gamelD) Tournament (tournamentName, tournamentWinner) 1. Write mySQL queries to generate the following tables: a. The total number of ongoing tournaments. b. The average number of players per game of type Power Grid. c. The names (no duplicates) of all players Abigail Baker beat in any game.
Given the following relation(s) and the functional dependencies, what is the highest normal form the data model complies to? Note: Primary keys are indicated in bold. TaxiRide (jobID, jobDateTime, driverID, driverName, taxiID, clientID, clientName, jobPickUpAddress)jobID -> jobDateTime, driverID, driverName, taxiID, clientID, clientName, jobPickUpAddressjobDateTime, driverID -> jobID, driverName, taxiID, clientID, clientName, jobPickUpAddressjobDateTime, taxiID -> jobID, driverID, driverName, clientID, clientName, jobPickUpAddressjobDateTime, clientID -> jobID, driverID, driverName, taxiID, clientName, jobPickUpAddressdriverID -> driverName, taxiIDclientID -> clientName A)1NF B)2NF C)3NF
entities: Residential students which fields like student id, Student name, exam papersTransfer students with fields like student id, transferred school, exam papers etc.Exam papers with fields like subjects, total marks, invigilator, checkers.Exam center with fields like Center Id, location, seating capacity etc. -Create an ER Diagram using the enumerated entities.
A relation FarmVisit is defined below with attributes in the table headings. FarmVisit visitorID visitorName date farmID farmName t1 H001 John 1 Feb 2021 A10 Green Field t2 Н005 Ashley 1 Jan 2021 A10 Green Field t3 но05 Ashley 1 Feb 2021 A10 Green Field t4 H005 Ashley 15 Apr 2021 H02 Есо t5 Но06 Ashley 15 Apr 2021 A11 Green Field a) Write down examples of tuples (i.e., tl, t2) to show neither of the following is a functional dependency: (i) visitorID -> date (ii) date -> farmID b) Write down the functional dependency (FDs) using the above data, which can represent all possible data. The FDs should be non-trivial and the determinants of the FDs should contain minimal number of attributes required. c) Using the tuples given, can (visitorID, farmID) be the primary key of FarmVisit? Explain why. d) What the highest normal form by which the FarmVisit relation can be classified? Explain why.
Let's break down the information into entities, attributes, and relationships: Entities: 1. Ship - ShipID (Primary Key) - ShipName - ShipType 2. Captain - CaptainID (Primary Key) - CaptainName - CaptainLicense 3. ShipmentTrip - TripID (Primary Key) - DeparturePort - ArrivalPort - RouteDetails 4. ShipmentManifest - ManifestID (Primary Key) - Date - GoodsList 5. Goods - GoodsID (Primary Key) - GoodsName - GoodsType (BM or LM) 6. Port - PortID (Primary Key) - Street - City - State - PostalCode - Country Relationships: - Ship to ShipmentTrip (Many-to-Many): - Ship can participate in multiple ShipmentTrips, and a ShipmentTrip can involve multiple Ships. Create a junction table `Ship_ShipmentTrip` with attributes `ShipID` and `TripID`. - Captain to ShipmentTrip (Many-to-Many): - A Captain can be assigned to multiple ShipmentTrips, and a ShipmentTrip can have multiple Captains. Create a junction table `Captain_ShipmentTrip` with attributes `CaptainID` and `TripID`. - Captain to Ship…
create an Entity Relationship Diagram using the following Entities and their respective attritubes for an online programming competition registration for both leaners and university students. 1. Host it's attributes (host Id, hostFirstName,hostLastName, hostTelNum,hostEmail,hostPassword) 2. Student(StudentId, StudentfirstName, Student Email, StudentPassword, InstitutionName) 3. Learners(leaner Id, leanerFirstName, leanerLastName, leanerPassword, SchoolName) 4. Competition(compId, comName, compDate,comTime, compRules, compRequirements) 5. Qualified Student/Leaner (id, firstName, compId,email)
Give a detailed explaination of the class diagram below
courses dasses ↑coursel INT courseDateTime DATETIME O room INT coursel INT courseName VARCHAR(45) course Description VARCHAR(45) room are used by a class. For each entity: Entitios rooms Froom DVT L-building VARCHAR(X) capacity VARCHAR(45) Inders The ERD depicts the data needed to track which course and Indicate if the entity is strong, weak ID-dependent, or weak non-ID-dependent For each relationship: • List the cardinality and participation of each entity in the relationship List the business rules for each relationship Indicate if the relationship is identifying or not