Based on the data shown below, calculate the regression line (each value to two decimal places)y%3D412.8615.36.16.3416.688.21.1219.261022.71122.841226.481328.12Question Help:Video Message instructorSubmit Question5.

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Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Run a regression analysis on the following bivariate set of data with y as the response variable. x y 43.2 -8.5 114.8 171 73.3 87.5 58.4 57.9 68.2 37.2 70.6 90.4 61.4 82.1 87.1 79.6 58 -9.2 78.4 77.2 80.5 87.3 64.1 22.9 54.3 32 Verify that the correlation is significant at an α=0.05α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 20.7 on the response variable.What is the predicted explanatory value?x = (Report answer accurate to one decimal place.)
Based on the data shown below, calculate the regression line (each value to two decimal places)y = x + x y 4 26.54 5 26.95 6 31.56 7 33.97 8 35.18 9 36.29
Run a regression analysis on the following bivariate set of data with y as the response variable. x y -9.7 -66.2 5.6 28.3 -4.5 11.9 35.6 94.9 15.7 21.1 30.8 86.3 48.7 127.9 13 57.3 35.3 109 23.6 32.4 58 166.3 28.1 64.4 19.1 51.5 25.6 53.3 46.1 186.4 43.5 128 Predict what value (on average) for the response variable will be obtained from a value of 14.8 as the explanatory variable. Use a significance level of α=0.05 to assess the strength of the linear correlation.What is the predicted response value? y =
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Run a regression analysis on the following bivariate set of data with y as the response variable. x y 85.1 61.8 40.6 -11.4 36.9 -15.1 72.5 47.9 62 41.8 74.2 19.4 91.3 55.4 57.7 -2.1 84.5 52.1 94.2 55.2 87.8 83.3 51.3 7.1 58.4 -4.9 72.3 16.7 72.6 35.4 71.3 19.2 64.4 16.7 Verify that the correlation is significant at an α=0.05α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 72.4 on the response variable.What is the predicted explanatory value?x =
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 34.4 51.4 21.3 55.8 42.1 45.1 46 44.3 16.6 64 45.5 45.9 41.8 38.8 20.8 56.6 27.6 52.9 12 66.2 35.6 52.4 21.6 57.4 Predict what value (on average) for the response variable will be obtained from a value of 36.9 as the explanatory variable. Use a significance level of α=0.05α=0.05 to assess the strength of the linear correlation.What is the predicted response value?y = (Report answer accurate to one decimal place.)
Based on the data shown below, calculate the regression line (each value to two decimal places) %3D y 13.28 13.41 13.94 8. 10.37 9. 13.7 10 11.03 11 12.46 12 9.99 13 8.82 14 10.55 15 9.18 16 9.81 17 9.84 18 9.47 19 9.2 670
Write out the regression equation using the information from the table: Variable Est. S.E. t p-value 95% Confidence Interval Race 5.20 1.05 Party 7.54 0.14 7.26, 7.82 Income 0.31 0.65 0.48 -0.96 , 1.58 Intercept 15.00 1.13 13.31 0.000 12.77, 17.18
Based on the data shown below, calculate the regression line. y 1 4.27 3.64 3 3.31 5.08 5.85 6. 2.42 y = [three decimal accuracy] [three decimal accuracy] 45
Next Run a regression analysis on the following bivariate set of data with y as the response variable. X y 48.1 41 63.7 62.6 40.1 33.4 49.4 46.3 16.3 -29.1 39.9 27.3 37.1 33.3 48.2 45.4 32.9 11.1 34.9 27.9 44.6 25.5 25.1 Z 23.2 Find the correlation coefficient and report it accurate to three decimal places. What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.) r² = % Submit Question

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Based on the data shown below, calculate the regression line (each value to two decimal places) y%3D 4 12.86 15.3 6. 16.34 16.68 8. 21.12 19.26 10 22.7 11 22.84 12 26.48 13 28.12 Question Help: Video Message instructor Submit Question 5.