Based on the data shown below, calculate the correlation coefficient (to three decimal places). This is theT value you get when you do the regression.19.456.22.6722.5526.39.27.351025.91129.951228.81330.25Submit Question9MB目hpCe

Based on the data shown below, calculate the correlation coefficient (to three decimal places). This is the I value you get when you do the regression. y 19.45 6. 22.6 7 22.55 26.3 9. 27.35 10 25.9 11 29.95 12 28.8 13 30.25

Based on the data shown below, calculate the correlation coefficient (to three decimal places). This is the I value you get when you do the regression. y 19.45 6. 22.6 7 22.55 26.3 9. 27.35 10 25.9 11 29.95 12 28.8 13 30.25

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Annual high temperatures in a certain location have been tracked for several years. Let XX represent the year and YY the high temperature. Based on the data shown below, calculate the correlation coefficient (to three decimal places) between XX and YY. Use your calculator! x y 4 20.48 5 19.1 6 23.52 7 23.34 8 23.56 9 23.98 r=
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 58.3 81.3 77.7 48.5 49.3 67.2 68.5 58.9 46.4 93.1 65.5 75.8 48.9 90.5 65.2 66.9 63.2 79.4 56.5 89.3 65.6 75.5 40.4 96.2 Find the correlation coefficient and report it accurate to three decimal places. r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.)r² = %Based on the data, calculate the regression line (each value to three decimal places)y = x + Predict what value (on average) for the response variable will be obtained from a value of 77.8 as the explanatory variable. Use a significance level of α=0.05 to assess the strength of the linear correlation.What is the predicted response value? (Report answer accurate to one decimal place.)y =
K The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 63 inches. Is the result close to the actual weight of 532 pounds? Use a significance level of 0.05. Chest size (inches) Weight (pounds) Click the icon to view the critical values of the Pearson correlation coefficient r. 58 50 65 59 59 48 D 414 312 499 450 456 260 =+x (Round to one decimal place as needed.) What is the best predicted weight of a bear with a chest size of 63 inches? The best predicted weight for a bear with a chest size of 63 inches is 566 pounds. 3 ▸
The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 40 inches. Is the result close to the actual weight of 352 pounds? Use a significance level of 0.05. Chest size (inches) *Weight (pounds) 44 54 328 528 41 55 39 51 418 580 296 503 Click the icon to view the critical values of the Pearson correlation coefficient r. - What is the regression equation? x (Round to one decimal place as needed.)
Run a regression analysis on the following bivariate set of data with y as the response variable. y 62.8 75.2 60 70.4 59.8 63 59.3 68.5 59 70.3 52.4 50.8 63.4 61.9 70.3 68.1 65.6 69.3 56.8 60.9 67.5 77.5 55.5 57.2 Find the correlation coefficient and report it accurate to three decimal places. What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.) r2 = Based on the data, calculate the regression line (each value to three decimal places) y = Predict what value (on average) for the response variable will be obtained from a value of 52.5 as the explanatory variable. Use a significance level of a = 0.05 to assess the strength of the linear correlation. What is the predicted response value? (Report answer accurate to one decimal place.) y = Submit Question IO 01 100 O Details
Annual high temperatures in a certain location have been tracked for several years. Let XX represent the year and YY the high temperature. Based on the data shown below, calculate the correlation coefficient (to three decimal places) between XX and YY. Use your calculator! x y 2 16.7 3 13.74 4 14.78 5 14.32 6 14.66 7 13.4 r=
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Run a regression analysis on the following bivariate set of data with y as the response variable. X 109.4 69.8 90 87.5 64.1 59.6 63.1 92.2 74.7 61.5 83.3 80.3 58.9. 57.3 73 y 61.4 51.6 38.6. 83.7 71.5 69.5 35.4 79.9 40.5 Find the correlation coefficient and report it accurate to three decimal places. r= Based on the data, calculate the regression line (each value to three decimal places) y' = X +
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 57.9 -34.4 16.6 92 40.1 89 55.8 54.5 57.9 27.4 17.3 164.1 65.2 62.4 48.3 51.9 66.2 14.5 70.9 -39.2 57 -90.1 58.5 63 Find the correlation coefficient and report it accurate to three decimal places.r = What proportion of the variation in y can be explained by the variation in the values of x? Report answer as a percentage accurate to one decimal place. (If the answer is 0.84471, then it would be 84.5%...you would enter 84.5 without the percent symbol.)r² = %
K Fit a regression line to the data shown in the chart, and find the coefficient of correlation for the line. Use the regression line to predict life expectancy in the year 2000, where x is the number of decades after 1900. year, x 0 (1900) life expectancy, y 49.1 years 51.4 years 2 (1920) 4 (1940) 53.0 years 6 (1960) 54.2 years 55.2 years 8 (1980) Choose the regression line. OA. y = 0.750x - 49.58 O C. y = 0.750x + 49.58 OB. y=49.58x + 0.750 = 49.58 ○ D. y = The life expectancy in the year 2000, rounded to one decimal place is years.
Based on the data shown below, calculate the correlation coefficient (to three decimal places). This is the 'r' value you get when you do the regression. x y 2 8.38 3 6.35 4 7.92 5 4.19 6 5.46 7 4.93 8 3.9
Run a regression analysis on the following data set with y as the response variable. x y 86.9 31.3 54.8 1.8 87.8 20.1 79.7 25.1 101 41 83 24.2 68.7 28.6 86.7 35.6 93.8 33.6 What is the predicted value of the response variable when the explanatory variable has value 78.87 Round your final answer to 1 decimal place.