Based on prior research, a wildlife researcher believes that the probability that a coyote carries fleas is 0.544. She would like to compute a confidence interval for the proportion of coyotes that have fleas in her particular area. She catches coyotes and checks them for fleas. How many coyotes would she have to check to specify the proportion of coyotes with fleas to within ±±0.051 with 90% confidence?

Q: A manufacturer claims that the average life of their fluorescent light bulbs is more than 2000…

A:

Q: If X = 117, o=24, and n = 30, construct a 99% confidence interval estimate of the population mean, µ

A: It is given that Sample size n = 30 Sample mean = 117 Population SD = 24

Q: A sample of size 16 was taken from a very large population. Sample statistics, x¯ and s, were used…

A: Formulae to find x¯ and s from confidence interval is as follows ,    x¯ = Lower limit +Upper limit…

Q: Based on responses of 1467 subjects in General Social Surveys, a 95% confidence interval for the…

A: Given Information: Based on responses of 1467 subjects in General Social Surveys, 95% confidence…

Q: A simple random sample of size n=40 is drawn from a population. The sample mean is found to be…

A: n=40 X-bar=121.2 S=13.2 99℅ confidence  interval

Q: Find a 94% confidence interval for A given that x = 20. a = 3. n = 30

A:

Q: A sample of size 36 has a mean X = 68. The population it is drawn from has a standard deviation = 3.…

A:

Q: A personal trainer determines that an individual will get the most benefit from a workout if they…

A: Given that

Q: A random sample of 100 Colorado residents is selected, and it is found that 82% of them have Subaru.…

A:

Q: Express the confidence interval (44.5 % , 55.1 % ) in the form of p ± E.

A: Given confidence interval is Lower limit=44.5 Upper limit=55.1   Express in form of p±E

Q: If X = 71, a= 14, and n =67, construct a 99% confidence interval estimato of the population moan,…

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Q: the standard deviation of the 16 observations was 0.95 inches (again, the sample mean was 17.2).…

A: Given :  Standard deviation of the 16 observations was 0.95 inches & the sample mean was 17.2.…

Q: For a sample 1000 app users, the research team reports an average age of 39. If the population…

A: given data  n = 1000 x¯ = 39σ = 9.590% ci, upper bound of ci  = ?

Q: In a random sample about advertising preferences, 17 out of 40 individuals said they preferred print…

A: Given,      Sample size n=40      and X=17      by using plus 4 method,      New sample size…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 400…

A: Given data, n=400 x=228 sample of proportion (p)= x/n = 228/400 = 0.57   The z value at 99%…

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: Given information

Q: A sample of 15 found that 43.2% of those sampled consumed more than 2 alcoholic  beverages  a week.…

A:

Q: A researcher estimates the 90% CI for a sample with a mean of M = 8.9 and a standard error (sM) of…

A:

Q: rvey is conducted to determine the average weekly hours of exercise for a sample of 50 adults. The…

A: given data, n=50df=n-1=50-1=49x¯=3.2s=1.5CI=0.99α=1-0.99=0.01

Q: A sample of size 84 was taken from a very large population. Sample statistics, x¯ and s, were used…

A:

Q: Suppose we know that a confidence interval is (27,35), with a margin of error of 4. Find the sample…

A: Let  the sample mean = x¯ given margin of error = E=4and confidence interval(27,35).

Q: A 95% confidence interval forp is given as (0.34,0.66). How large was the sample used to construct…

A: Formula for the sample size needed to estimate a population proportion is

Q: A random sample of high school students is used to estimate the mean time all high school students…

A: Solution: From the given information, a 99% confidence interval is 1.7 hours to 3.1 hours.

Q: If a 90% confidence interval for µ is [15, 25],  then X=?, e=?

A: Note: Hello! Thank You for the question. We are considering 'e' as margin of error. From the given…

Q: For a population of normally distributed scores, μ = 155 and σ = 12, approximately what would be the…

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Q: A sample of size 16 was taken from a very large population. Sample statistics, x¯ and s, were used…

A:

Q: In a study, Group 1 was found to have an average of 53 and a population standard deviation of 13 out…

A:

Q: Based on a sample of size 40, a 95% confidence interval for the mean score of all students, µ, on an…

A: we knows that,margin of error = Z a/2 * (standard error)confidence interval = x ± margin of…

Q: Find a 90% confidence interval for the population mean age of the Smurfs if a sample of 52 smurfs…

A: It is given that, There is a random sample of size 52 and has a mean of 49.7 and the standard…

Q: Suppose it is known that approximately 30% of households own a sin- gle TV. Use this to obtain the…

A: From the provided information, The proportion of household own a single TV (p) = 0.30 Margin of…

Q: If X=117, o=24, and n = 30, construct a 99% confidence interval estimate of the population mean, μ.…

A: GivenMean(x)=117standard deviation(σ)=24sample size(n)=30Confidence level=99%

Q: Out of a survey of 3200 people who own a hot tub, only 70% use it at least once each week. This was…

A: Solution: From the given information, p-hat is 70% and the margin of error is E=1.7%.

Q: Based on prior research, a wildlife researcher believes that the probability that a coyote carries…

A: It is given that margin of error (E) is 0.042 and the confidence level is 0.90.

Q: Suppose that the true population standard deviation (this assumption is made only for this question,…

A:

Q: A simple random sample of size n is drawn. The sample​ mean, x overbarx​, is found to be 18.6​, and…

A: From the provided information, Sample mean (x̅) = 18.6 Sample standard deviation (s) = 4.1 Sample…

Q: A sample of size 25 was taken from a very large population. Sample statistics, a and s, were used to…

A: For the given data Find mean =? s.d = ?

Q: sed on a sample of size 49, a 95% confidence interval for the mean scaore of all students, u, on an…

A: given data, n=49CI=0.95α=1-0.95=0.05confidence interval on an aptitude is from 59.2 to 64.8 margin…

Q: A study is to be conducted to estimate the daily water consumption per person. If the population…

A:

Q: The 85.7% confidence interval estimate for p was (0.14, 0.16). Find ?′ and ME

A:

Q: a sample 1000 website users, the research department reports an average age of 39. If the population…

A: GIVEN DATA,n=1000x¯=39σ=9.5CI=0.90α=1-0.90=0.10α/2=0.10/2=0.05we have to find out the upper bound…

Q: If n=29, x¯=48, and s=13, construct a confidence interval at a 90% confidence level. Assume the data…

A: The confidence level is 90%. Then the probability is 10%=100%-90%. The degrees of freedom is,…

Q: A study found that a 95% confidence interval for the mean μ of a particular population was computed…

A: Given, 95% confidence interval 10 ± 4  Sample size  = 1200         To write the conclusion regarding…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.