Based on a survey, we assume that 59% of students have a pet. Suppose that there are 4 students sitting at a table. Find the probability of each of these events. Give each probability as a percentage rounded to two decimal places. (a) What is the probability that all 4 students have a pet? (b) What is the probability that none of the 4 students have a pet? % (c) What is the probability that at least one of the 4 students have a pet? % %

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 14CR
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**Probability Exercise for Students**

Based on a survey, we assume that 59% of students have a pet. Suppose that there are 4 students sitting at a table.

Find the probability of each of these events. **Give each probability as a percentage rounded to two decimal places.**

(a) What is the probability that **all 4 students have a pet?** [_____]% 

(b) What is the probability that **none of the 4 students have a pet?** [_____]% 

(c) What is the probability that **at least one of the 4 students have a pet?** [_____]%
Transcribed Image Text:**Probability Exercise for Students** Based on a survey, we assume that 59% of students have a pet. Suppose that there are 4 students sitting at a table. Find the probability of each of these events. **Give each probability as a percentage rounded to two decimal places.** (a) What is the probability that **all 4 students have a pet?** [_____]% (b) What is the probability that **none of the 4 students have a pet?** [_____]% (c) What is the probability that **at least one of the 4 students have a pet?** [_____]%
Expert Solution
Step 1

Given:

The number of students sitting at a table is n=4.

The percentage of students having pet is p=0.59.

We need to determine the probability of the events given.

Concept: We use the Binomial probability law which is given by;

P(X=x)=C(n,x) px q(n-x); x0

where n is the number of trialsp is the probability of successC(n,x)=n!x!(n-x)! and n!=n×n-1×...×2×1

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