### Transcription for Educational Use**Scenario:**Based on a smartphone survey, assume that 55% of adults with smartphones use them in theaters. In a separate survey of 234 adults with smartphones, it is found that 127 use them in theaters.**Questions:**a. If the 55% rate is correct, find the probability of getting 127 or fewer smartphone owners who use them in theaters.b. Is the result of 127 significantly low?**Instructions:**a. Calculate the probability of getting 127 or fewer smartphone owners who use them in theaters, assuming the 55% rate is accurate.- **Note:** Round to four decimal places as needed.b. Determine if the result of 127 is significantly low by comparing the probability to the significance cutoffs provided.- Choose the appropriate option based on probability comparison: - 0.5 - 0.95 - 0.05**Submission:**Enter your answer in the provided answer box.### Explanation of Components- **Text Box:** This is where you input your calculation answer.- **Dropdown Menu:** Offers probability values as options to assist in determining if the result is significant.

Solution: Given information: Let X be the random variable of adults used smartphone in the theater the probability of random variable X is p = 0.55 q= 1-p=0.45 n= 234 Sample size This is an binomial experiment with parameters n=234 and p=0.55 We used normal approximation to binomial distribution when np and nq both are grater than or equal to 10 np=234×0.55=128.7 ≥10nq=234×0.455=105.3≥10 both are greater that or equal to 10 we used normal approximation to binomial distribution. mean=μ=np=234×0.55=128.7Standard deviations = σ=npqStandard deviations = σ=234×0.55×0.45Standard deviations = σ=57.915Standard deviations = σ=7.6101905Standard deviations = σ=7.6102 a) To find the probability that 127 or fever smartphone owner used smartphone in theater that is to find P(X<127) P(X<127)=P(X-μσ<127-μσ)=P(N(0,1)<127-128.77.6102)=P(Z<-1.77.6102)=P(Z<-0.223384)=P(Z<-0.22)= 0.4129 From standard normal Z tableP(X<127)=0.4129 The probability that 127 or fever smartphone owner used smartphone in theater is 0.4129 b) No because the probability of this event is greater than probability cutoff that corresponds to significant event 0.05

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Based on a smartphone survey, assume that 55% of adults with smartphones use them in theaters. In a separate survey of 234 adults with smartphones, it is foun hat 127 use them in theaters. a. If the 55% rate is correct, find the probability of getting 127 or fewer smartphone owners who use them in theaters. p. Is the result of 127 significantly low? a. If the 55% rate is correct, the probability of getting 127 or fewer smartphone owners who use them in theaters is Round to four decimal places as needed.) b. Is the result of 127 significantly low? than the probability cutoff that corresponds to a significant event, which v 0.5. because the probability of this event is 0.95. 0.05.

Based on a smartphone survey, assume that 55% of adults with smartphones use them in theaters. In a separate survey of 234 adults with smartphones, it is foun hat 127 use them in theaters. a. If the 55% rate is correct, find the probability of getting 127 or fewer smartphone owners who use them in theaters. p. Is the result of 127 significantly low? a. If the 55% rate is correct, the probability of getting 127 or fewer smartphone owners who use them in theaters is Round to four decimal places as needed.) b. Is the result of 127 significantly low? than the probability cutoff that corresponds to a significant event, which v 0.5. because the probability of this event is 0.95. 0.05.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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