Based on a sample of 80 textbooks at the store, you find an average of 58.24 and a standarddeviation of 15.6.The point estimate is:(to 3 decimals)The 90 % confidence interval (use z*) is:to(to 3decimals)FEB8.Wesc20F1F2F3F4F5F6F7#243.4WRTYtabSGH.caps lockCB B AQuestion 8>Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at BCbookstore costs $ 58.84. You want to test this claim.The null and alternative hypothesis in symbols would be:Ο Η: μ > 58.84H1: µ < 58.84O Ho:p = 58.84H1:p + 58.84O Ho:p > 58.84H1:p < 58.84Ο Η: μ < 58.84H1:µ > 58.84O Ho:p < 58.84H1:p > 58.84Ο Η: μ 58.84H1:µ # 58.84FEB8.W20escF1F2F3F4F5F6F7F8%23%&134WRTtabScaps lockCVBLLA.

The best estimate which is given for a population parameter is known as "point estimate". As from…

Based on a sample of 80 textbooks at the store, you find an average of 58.24 and a standard deviation of 15.6. The point estimate is: (to 3 decimals) The 90 % confidence interval (use z*) is: (to 3 to decimals)

Based on a sample of 80 textbooks at the store, you find an average of 58.24 and a standard deviation of 15.6. The point estimate is: (to 3 decimals) The 90 % confidence interval (use z*) is: (to 3 to decimals)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

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Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

100%

Based on a sample of 80 textbooks at the store, you find an average of 58.24 and a standard
deviation of 15.6.
The point estimate is:
(to 3 decimals)
The 90 % confidence interval (use z*) is:
to
(to 3
decimals)
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B A
Question 8
>
Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at BC
bookstore costs $ 58.84. You want to test this claim.
The null and alternative hypothesis in symbols would be:
Ο Η: μ > 58.84
H1: µ < 58.84
O Ho:p = 58.84
H1:p + 58.84
O Ho:p > 58.84
H1:p < 58.84
Ο Η: μ < 58.84
H1:µ > 58.84
O Ho:p < 58.84
H1:p > 58.84
Ο Η: μ 58.84
H1:µ # 58.84
FEB
8.
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20
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F1
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F3
F4
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3
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A.

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