Ba(OH), is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.550 M Ba(OH), solution. [Ba²*1 = [OH ] =

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**Topic: Determining Ion Concentrations in a Strong Electrolyte Solution**

**Description:**

Ba(OH)₂ is a strong electrolyte.

**Objective:**

Determine the concentration of each of the individual ions in a 0.550 M Ba(OH)₂ solution.

**Concentration Calculations:**

- \([ \text{Ba}^{2+} ] =\) 
- \([ \text{OH}^- ] =\) 

**Explanation:**

Since Ba(OH)₂ is a strong electrolyte, it dissociates completely in solution:

\[ \text{Ba(OH)}_2 \rightarrow \text{Ba}^{2+} + 2\text{OH}^- \]

Given the original concentration of Ba(OH)₂ is 0.550 M, this means:

- The concentration of \(\text{Ba}^{2+}\) ions will be 0.550 M, because each formula unit of Ba(OH)₂ yields one \(\text{Ba}^{2+}\) ion.
- The concentration of \(\text{OH}^-\) ions will be 1.100 M, because each formula unit yields two \(\text{OH}^-\) ions.

**Question Source:** MRG - General Chemistry

**Additional Resources:**

For further understanding of electrolytes and dissociation, explore our comprehensive guides on chemical solutions.

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Transcribed Image Text:**Topic: Determining Ion Concentrations in a Strong Electrolyte Solution** **Description:** Ba(OH)₂ is a strong electrolyte. **Objective:** Determine the concentration of each of the individual ions in a 0.550 M Ba(OH)₂ solution. **Concentration Calculations:** - \([ \text{Ba}^{2+} ] =\) - \([ \text{OH}^- ] =\) **Explanation:** Since Ba(OH)₂ is a strong electrolyte, it dissociates completely in solution: \[ \text{Ba(OH)}_2 \rightarrow \text{Ba}^{2+} + 2\text{OH}^- \] Given the original concentration of Ba(OH)₂ is 0.550 M, this means: - The concentration of \(\text{Ba}^{2+}\) ions will be 0.550 M, because each formula unit of Ba(OH)₂ yields one \(\text{Ba}^{2+}\) ion. - The concentration of \(\text{OH}^-\) ions will be 1.100 M, because each formula unit yields two \(\text{OH}^-\) ions. **Question Source:** MRG - General Chemistry **Additional Resources:** For further understanding of electrolytes and dissociation, explore our comprehensive guides on chemical solutions. **Navigation:** - [About Us](#) - [Careers](#) - [Privacy Policy](#) - [Terms of Use](#) - [Contact Us](#) - [Help](#)
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