Please answer and solve the question correctly. Thank you! **Problem Statement:**A ball is released from a height of 12 meters and weighs 35 newtons. What is the magnitude \(|\Delta U|\) of the total change in potential energy when the ball falls to the ground?**Answer Box:**\(|\Delta U|\) [J]**Explanation:**This question asks for the calculation of the change in potential energy as a ball is released from a certain height until it hits the ground. The following concepts will help in understanding:- **Gravitational Potential Energy (\(U\))**: This is calculated using the formula \(U = m \cdot g \cdot h\), where \(m\) is the mass, \(g\) is the gravitational acceleration (\(9.81 \ \text{m/s}^2\) on Earth), and \(h\) is the height.- **Change in Potential Energy (\(\Delta U\))**: This is the difference between the initial and final potential energies. Since the ball falls to the ground, the final potential energy is zero.To find \(|\Delta U|\), the magnitude of the change in potential energy, use:1. Initial potential energy \(U_i = m \cdot g \cdot h\).2. Final potential energy \(U_f = 0\).3. \(|\Delta U| = |U_f - U_i|\).Since \(U_f = 0\), \(|\Delta U| = U_i\).Given:- Height (\(h\)) = 12 m- Weight (force due to gravity, \(m \cdot g\)) = 35 NPlug these into the equation to solve for \(|\Delta U|\).

Name: Please answer and solve the question correctly. Thank you! **Problem S
Uploaded: 2024-03-20T06:57:25.000Z
Channel: Bartleby
Description: Please answer and solve the question correctly. Thank you! **Problem Statement:**A ball is released from a height of 12 meters and weighs 35 newtons. What is the magnitude \(|\Delta U|\) of the total change in potential energy when the ball falls to