balanced equation: 2 Al (s) + 2 KOH (aq) + 4 H2SO4 (aq) + 22 H2O (l) → 2 (KAl(SO4)2∙12H2O ) (s) + 3 H2 (g) Given: mass of Al: 0.49 g volume of 1.4 M KOH: 0.025 L volume of 9 M H2SO4: 0.0102 L mass of watch glass: 50.28 g mass of watch glass + alum: 58. 17 g Al= 0.01815 moles (limited reactant) KOH= 0.035 moles H2SO4= 0.0918 Question: Your product is a hydrate, meaning that when the crystals are completely dry, there are still water molecules bound inside them. Specifically, it's a "dodeca" hydrate because that's how chemists say 12. This is important because those waters influence the molecular mass (g/mol) of your product Find molecular mass of alum: Molecular mass of alum: _________ Based on the balanced equation (if the reaction went perfectly and you didn't spill a single drop or lose one crystal) how much product could you make? this is the theoretical yield. Find Moles of Alum(Theoretical) : ________ Find Mass of Alum (Theoretical): _________ Find Mass of Alum (Actual): ________ Find the Percent Yield of Alum: _______
balanced equation: 2 Al (s) + 2 KOH (aq) + 4 H2SO4 (aq) + 22 H2O (l) → 2 (KAl(SO4)2∙12H2O ) (s) + 3 H2 (g)
Given: mass of Al: 0.49 g
volume of 1.4 M KOH: 0.025 L
volume of 9 M H2SO4: 0.0102 L
mass of watch glass: 50.28 g
mass of watch glass + alum: 58. 17 g
Al= 0.01815 moles (limited reactant)
KOH= 0.035 moles
H2SO4= 0.0918
Question: Your product is a hydrate, meaning that when the crystals are completely dry, there are still water molecules bound inside them. Specifically, it's a "dodeca" hydrate because that's how chemists say 12. This is important because those waters influence the molecular mass (g/mol) of your product
Find molecular mass of alum:
Molecular mass of alum: _________
Based on the balanced equation (if the reaction went perfectly and you didn't spill a single drop or lose one crystal) how much product could you make? this is the theoretical yield.
Find Moles of Alum(Theoretical) : ________
Find Mass of Alum (Theoretical): _________
Find Mass of Alum (Actual): ________
Find the Percent Yield of Alum: _______
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