Balance the redox equation using the half reaction method. Show stepwise reaction , separating the oxidizer from the reducer) Sn 2* +( 103) -→ Sn 4+ (acid) 2. ( MnO4 ) + SO, --→ Mn 2* + (SO4 ) 2- (acid) 3. Cr,0,2- + Ci -> Cr 3+ + Cl2 (acid )

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Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.101QP: Balance the following skeleton equations. The reactions occur in acidic or basic aqueous solution,...
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Balance the redox equation using the half reaction method . Show stepwise reaction , separating the
oxidizer from the reducer)
Sn 2* +( 103) - -→ Sn 4+
(acid)
2. ( MnO4 ) + SO2 --→ Mn 2* + (SO4) 2-
(acid)
3. Cr,0,2- + ci- ->
Cr 3+
+ Cl2
(acid )
4. ( Cro4 ) 2- + (HSNO2) · → (HSnO3) · + (CrO2) ·
(base)
5. (Cro2) + ( CIO) - -→ (Cro4 ) 2 + CI-
(base)
Transcribed Image Text:Balance the redox equation using the half reaction method . Show stepwise reaction , separating the oxidizer from the reducer) Sn 2* +( 103) - -→ Sn 4+ (acid) 2. ( MnO4 ) + SO2 --→ Mn 2* + (SO4) 2- (acid) 3. Cr,0,2- + ci- -> Cr 3+ + Cl2 (acid ) 4. ( Cro4 ) 2- + (HSNO2) · → (HSnO3) · + (CrO2) · (base) 5. (Cro2) + ( CIO) - -→ (Cro4 ) 2 + CI- (base)
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