Balance the following redox reaction in acidic aqueous conditions:Br + NO2 + BrOg + N2How many H are in the final overall balanced reaction?3 on the righter2 on the leftnone3 on the left2 on the right

Oxidation states of Br – In Br- = -1 In BrO3- = +5 Oxidation states of N – In NO2- = +3 for 1 N. In N2 = 0 for both NHalf reactions – Br-→BrO3- + 6e-Oxygen and H balance in acidic medium -Br-+3H2O→BrO3- + 6e-+6H+....(1)2NO2-+ 6e-→N2Oxygen and H balance in acidic medium -2NO2-+ 6e-+8H+→N2+4H2O....(2)Add both equations - Br-+3H2O+2NO2-+ 6e-+8H+→BrO3- + 6e-+6H++N2+4H2OCancel common terms -Br-+2NO2-+2H+→BrO3- +N2+H2ONumber of H+ in 2 and on the left side of reaction or towards reactants So the correct option is (b) 2 on the left side.

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Balance the following redox reaction in acidic aqueous conditions: Br + NO2 -→ BrO + N2 How many H* are in the final overall balanced reaction? 3 on the right 2 on the left none 3 on the left 2 on the right

Balance the following redox reaction in acidic aqueous conditions: Br + NO2 -→ BrO + N2 How many H* are in the final overall balanced reaction? 3 on the right 2 on the left none 3 on the left 2 on the right

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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