Balance the following redox equations by the half-reaction method: (a) Mn²* + H,O2 → MnO, + H,O (in basic solution) (b) Bi(OH)3 + SnO,²→ SnOz²¯ + Bi (in basic solution) (C) Cr,0,?- + C,0,²- → Cr* + CO, (in acidic solution) (d) Cl0,¯ + CI¯ → Cl2 + C1O, (in acidic solution) (e) Mn2* + BiO3– Bi* + MnO, (in acidic solution)
Balance the following redox equations by the half-reaction method: (a) Mn²* + H,O2 → MnO, + H,O (in basic solution) (b) Bi(OH)3 + SnO,²→ SnOz²¯ + Bi (in basic solution) (C) Cr,0,?- + C,0,²- → Cr* + CO, (in acidic solution) (d) Cl0,¯ + CI¯ → Cl2 + C1O, (in acidic solution) (e) Mn2* + BiO3– Bi* + MnO, (in acidic solution)
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Balance the following redox equations by the half-reaction method:
(a) Mn²* + H,O2 → MnO, + H,O (in basic solution)
(b) Bi(OH)3 + SnO,²→ SnOz²¯ + Bi (in basic solution)
(C) Cr,0,?- + C,0,²- → Cr* + CO, (in acidic solution)
(d) Cl0,¯ + CI¯ → Cl2 + C1O, (in acidic solution)
(e) Mn2* + BiO3– Bi* + MnO, (in acidic solution)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38f5a6cf-9797-4708-805b-9e7bf780a333%2F65ebfe63-8001-4c5f-8ddc-6e5148505093%2F0a3ky0f.png&w=3840&q=75)
Transcribed Image Text:Balance the following redox equations by the half-reaction method:
(a) Mn²* + H,O2 → MnO, + H,O (in basic solution)
(b) Bi(OH)3 + SnO,²→ SnOz²¯ + Bi (in basic solution)
(C) Cr,0,?- + C,0,²- → Cr* + CO, (in acidic solution)
(d) Cl0,¯ + CI¯ → Cl2 + C1O, (in acidic solution)
(e) Mn2* + BiO3– Bi* + MnO, (in acidic solution)
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