Balance the following Oxidation Reduction reaction using either the half reduction method or the oxidation number method.

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13) Balance the following Oxidation Reduction reaction using either the half reduction method or the oxidation number method. 

**Chemical Reaction in Basic Solution**

In this reaction, the chlorate ion (\( \text{ClO}_3^- \)) reacts with iodine (\( \text{I}_2 \)), resulting in the formation of the iodate ion (\( \text{IO}_3^- \)) and the chloride ion (\( \text{Cl}^- \)). 

This process occurs in a basic solution:

\[ \text{ClO}_3^- + \text{I}_2 \rightarrow \text{IO}_3^- + \text{Cl}^- \]

This equation represents a redox reaction where the oxidation states of chlorine and iodine change, and it highlights the behavior of these ions in a basic environment.
Transcribed Image Text:**Chemical Reaction in Basic Solution** In this reaction, the chlorate ion (\( \text{ClO}_3^- \)) reacts with iodine (\( \text{I}_2 \)), resulting in the formation of the iodate ion (\( \text{IO}_3^- \)) and the chloride ion (\( \text{Cl}^- \)). This process occurs in a basic solution: \[ \text{ClO}_3^- + \text{I}_2 \rightarrow \text{IO}_3^- + \text{Cl}^- \] This equation represents a redox reaction where the oxidation states of chlorine and iodine change, and it highlights the behavior of these ions in a basic environment.
Expert Solution
Step 1 Balancing of redox reactions

 

Half reaction method

Step-1 : write the skeletal equation and indicate oxidation state of each element

Step-2 : Find out species which are oxidised and which are reduced

Step-3 : Split the skeletal equation into two half reaction. 

Step-4 :  Balance the two half reaction equations seperately by the rules described below 

 

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